Help please!!!! 10 points

Darren wanted to see how contagious yawning can be. To better understand this, he conducted a social experiment in which he yawn

denis23 [38]

Answer:

10.5 minutes

Step-by-step explanation:

Thinking about the problem

The modeling function is of the form P(t)=A⋅Bf(t), where B=4B=4B, equals, 4 and f(t)=\dfrac{t}{10.5}f(t)=

10.5

t

f, left parenthesis, t, right parenthesis, equals, start fraction, t, divided by, 10, point, 5, end fraction.

Note that each time f(t)f(t)f, left parenthesis, t, right parenthesis increases by 111, the quantity is multiplied by B=4B=4B, equals, 4.

Therefore, we need to find the ttt-interval over which f(t)f(t)f, left parenthesis, t, right parenthesis increases by 111.

Hint #22 / 3

Finding the appropriate unit interval

fff is a linear function whose slope is \dfrac{1}{10.5}

10.5

1

start fraction, 1, divided by, 10, point, 5, end fraction.

This means that whenever ttt increases by \Delta tΔtdelta, t, f(t)f(t)f, left parenthesis, t, right parenthesis increases by \dfrac{\Delta t}{10.5}

10.5

Δt

start fraction, delta, t, divided by, 10, point, 5, end fraction.

Therefore, for f(t)f(t)f, left parenthesis, t, right parenthesis to increase by 111, we need \Delta t=10.5Δt=10.5delta, t, equals, 10, point, 5. In other words, the ttt-interval we are looking for is 10.510.510, point, 5 minutes.

Hint #33 / 3

Summary

The number of people who yawned quadruples every 10.510.510, point, 5 minutes.

7 0

4 years ago

A doctor is measuring the average height of male students at a large college. The doctor measures the heights, in inches, of a s

RoseWind [281]

Answer:

There is a 95% confidence that the true mean height of all male student at the large college is between the interval (63.5, 74.4).

Step-by-step explanation:

The (1 - α)% confidence interval for population mean is:

$CI=\bar x\pm z_{\alpha/2}\times\frac{\sigma}{\sqrt{n}}$

The (1 - α)% confidence interval for population parameter implies that there is a (1 - α) probability that the true value of the parameter is included in the interval.

Or, the (1 - α)% confidence interval for the parameter implies that there is (1 - α)% confidence or certainty that the true parameter value is contained in the interval.

The 95% confidence interval for the average height of male students at a large college is, (63.5 inches, 74.4 inches).

The 95% confidence interval for the average height of male students (63.5, 74.4) implies that, there is a 0.95 probability that the true mean height of all male student at the large college is between the interval (63.5, 74.4).

Or, there is a 95% confidence that the true mean height of all male student at the large college is between the interval (63.5, 74.4).

4 0

4 years ago

HELP!!!! -5 3/4 - 3 1/2 = ?

umka21 [38]

Answer:

9.25 or 9 1/4

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Need help ASAP. Last two problems on my study guide, can't seem to solve them?

Dimas [21]

Answer:

9) 4

10) p¹⁵/q⁹

Step-by-step explanation:

9)

As per the law of indices, (xᵃ)ᵇ=xᵃᵇ.

So divide 8 by 2 to get 4

10)

p(p⁻⁷q³)⁻²q⁻³

p(p¹⁴q⁻⁶)q⁻³ (because (xᵃ)ᵇ=xᵃᵇ)

pq⁻³(p¹⁴q⁻⁶)

p¹⁵q⁻⁹

p¹⁵/q⁹ (because x⁻ᵃ =1 /xᵃ)

4 0

3 years ago

I need help with this ^^ It’s about choosing a graph to fit a narrative

jenyasd209 [6]

1. The fourth graph: D
2. The first graph: A

3 0

3 years ago