Answer:
a) The interval for those who want to go out earlier is between 43.008 and 46.592
b) The interval for those who want to go out later is between 47.9232 and 51.9168
Step-by-step explanation:
Given that:
Sample size (n) =128,
Margin of error (e) = ±4% =
a) The probability of those who wanted to get out earlier (p) = 35% = 0.35
The mean of the distribution (μ) = np = 128 * 0.35 = 44.8
The margin of error = ± 4% of 448 = 0.04 × 44.8 = ± 1.792
The interval = μ ± e = 44.8 ± 1.792 = (43.008, 46.592)
b) The probability of those who wanted to start school get out later (p) = 39% = 0.39
The mean of the distribution (μ) = np = 128 * 0.39 = 49.92
The margin of error = ± 4% of 448 = 0.04 × 49.92 = ± 1.9968
The interval = μ ± e = 44.8 ± 1.792 = (47.9232, 51.9168)
The way for those who want to go out earlier to win if the vote is counted is if those who do not have any opinion vote that they want to go earlier
Step-by-step explanation:
Let's see. f(4) makes the divisor x-4
4|-2 9 -6 7
| 8 -68 296
-2 17 -74 2072
The quotient is -2x²+17x-74 with a remainder of 2072
4+6=10 6/10 60% that is the answer
