Answer:
One cm represented 5 m in the first scale, but now 1 cm represents 4 m in the second scale.
Step-by-step explanation:
s1+s2>s3 where s1 and s2 are the 2 smaller sides
Choice C is the only 1 that fits
7+13 >18
We need Pythagoras theorem here
a^2+b^2 = c^2
a, b = legs of a right-triangle
c = length of hypotenuse
Let S=shorter leg, in cm, then longer leg=S+2 cm
use Pythagoras theorem
S^2+(S+2)^2 = (10 cm)^2
expand (S+2)^2
S^2 + S^2+4S+4 = 100 cm^2 [collect terms and isolate]
2S^2+4S = 100-4 = 96 cm^2
simplify and form standard form of quadratic
S^2+2S-48=0
Solve by factoring
(S+8)(S-6) = 0 means (S+8)=0, S=-8
or (S-6)=0, S=6
Reject nengative root, so
Shorter leg = 6 cm
Longer leg = 6+2 cm = 8 cm
Hypotenuse (given) = 10 cm
T = 0
=> Q = 0
t = x
=> Q = arcsin(x/a)
rest it just simple integration of trigonometric function
Answer: The final answer I got is -44.9
Step-by-step explanation: At the first chose I put Positive, then at the second choise I put negative, at the third choose I put 16.8-(-28.1), and at the last choice I put -44.9.