First, the problem is g(f(x)). You would plug in f(x) wherever you see an x in g(x). To find the domain, you take the bottom function, and set it equal to 0.

$\sqrt{x-2} =0$

When you solve that, you get x=2. You know your domain is x≥2, but there is as asymptote at x=11. That means the graph never reaches x=11, but gets very close. You find that by setting the entire equation equal to 0 and solve from there.

5 0

3 years ago

Henry received $500 for his birthday which he intends to invest in an account that pays simple interest at the rate of 12% per y

Mila [183]

Answer:

$560

Step-by-step explanation:

Given that :

Principal, P= $500

Interest rate, r = 12% per year

Amount in account after 1 year

Time = 1 year

Using the relation :

A = P(1 + rt)

A = final amount in account

A = $500(1 + 0.12(1))

A = $500(1 + 0.12)

A = $500(1.12)

A = $560

3 0

2 years ago

A rectangular field has side lengths of 2/3 mile and 3/4 mile. What is the area of the field.

Ray Of Light [21]

A = LW
A = 2/3 * 3/4
A = 6/12 = 1/2 miles^2

4 0

3 years ago

2 hours of tv had 40 commercials __ __commercials per hour (Ratio/Rate)

2 hours of tv had 40 commercials commercials per hour (Ratio/Rate)