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State the vertex and axis of symmetry of the graph of y=ax^2+c
General form of quadratic equation is
There is no bx in our given equation, so we put 0x
Given equation can be written as
a=a , b=0
Now we use formula to find vertex
Now we plug in 0 for 'a' and find out y
So our vertex is (0,c)
The axis of symmetry at x coordinate of vertex
So x=0 is our axis of symmetry
Answer:
4/3 units
Step-by-step explanation:
The distance can be found using the pythagorean theorem.
The y-distance is 4 - (-4), which is 8.
The x-distance is 1 - (-5), which is 6.
√(6² + 8³) 10 units.
