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vfiekz [6]
4 years ago
6

Help Me With These #Geometry

Mathematics
1 answer:
cluponka [151]4 years ago
8 0
#4 is b. you use the law of sines to find the missing angles and side lengths.
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50 POINTS !!<br><br><br> PLEASE HELP AND EXPLAIN !! ILL GIVE BRAINLIEST TO THE RIGHT ANSWERS.
allochka39001 [22]
I need the point my point is -
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3 years ago
Read 2 more answers
3(x+10)=2(2x+16) help please &amp; thank you
andrew-mc [135]
In this question, you have to isolate <em>x</em>.

First, use the distributive property.

3x+30=4x+32

Now that you have distributed, subtract the constants. 


7 0
3 years ago
Mara carried water bottles to the field to share with her team at halftime. The water bottles weighed a total of 60x^2 + 48x + 2
VLD [36.1K]

Answer:

b)\: 12(5x^2+4x+2)

Step-by-step explanation:

The given expression for water bottles is

60x^2+48x+24.


The highest common factor of all the terms of this expression is 12.


We now factor to obtain;

12(5x^2+4x+2)

Hence the the factorization that represents the number of water bottles and the weight of each bottle is the one in option B.

The correct answer is B


We therefore factor to obtain,


3 0
3 years ago
Help please <br><br><br><br> Show two different ways to factor<br> -2x - 10
Arada [10]
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3 0
3 years ago
The equation of a circle is (x + 6)^2 + (y - 4)^2 = 16. The point (-6, 8) is on the circle.
pantera1 [17]

Answer:

y = 8 is the equation of tangent.

Step-by-step explanation:

The equation of the tangent to the circle at (-6,8) is of the form:

y = mx + c

where m is the slope of the tangent and c is the y-intercept.

The point (-6,8) lies on the circle and the tangent line as well.

Hence (-6,8) satisfies the line equation:

8 = m(-6) + c ⇒ c-6m = 8 -------------1

We know that slope of two perpendicular lines are related as:

m_{1}\times m_{2}=-1

At any point on the circle, the normal line at a point is always perpendicular to the tangent line at that point.

Hence :

m_{normal} \times m_{tangent}=-1

We can find the slope of the normal at point (-6,8) as it passes through the centre of the circle (-6,4) by using the two-points formula for slope.

m=\frac{y_2-y_1}{x_2-x_1}

         =\frac{8-4}{-6+6}

          = ∞

Slope of the normal is infinity and hence slope of tangent is -1/∞ = 0

Hence m=0

Putting m=0 in equation 1 we get:

c = 8

The equation of tangent line at (-6,8) is:

y = 8

6 0
3 years ago
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