Help Me With These #Geometry

7 times as much as the sum of 1/3 and 4/5

Jet001 [13]

First of all, you add 1/3 and 4/5, so you get:
$\frac{1}{3} + \frac{4}{5}$

To add 2 fractions, they need to have the same denominator. Since 3 and 5 don't have a common factor, so you multiply 1/3 by 5, and 4/5 by 3, so you get:
$\frac{1*5}{3*5} + \frac{4*3}{5*3}$
$\frac{5}{15} + \frac{12}{15}$

Now, the two fractions got the same denominator, and you can add them by adding the numerators over the same denominator. (You don't add denominators in addition) so you get:
$\frac{5+12}{15}$
$\frac{17}{15}$

That's the sum of 1/3 + 4/5.

Now, they want the sum of the 2 fractions 7 times. So you multiply 17/15 by 7. And as you know, 7 = 7/1. So you get:
$\frac{17}{15} * \frac{7}{1}$

In multiplication no need to have the same denominator. You multiply nominators by nominators and denominators by denominators. So you get:
$\frac{17*7}{15*1}$
$\frac{119}{15}$

Since 119 and 15 don't have a common factor, so they can't be simplified.
So, the answer is 119/15.

Hope this Helps! :D

7 0

3 years ago

Read 2 more answers

I need a real answer to this problem and if you can't answer then please don't answer this. Just give me the answer for the blan

Harlamova29_29 [7]

To divide the triangles into these regions, you should construct the <u>perpendicular bisector</u> of each segment.
These perpendicular bisectors intersect and divide each triangle into three regions.
The points in each region are those closest to the vertex in that <u>region</u>.

<h3>What is a triangle?</h3>

A triangle can be defined as a two-dimensional geometric shape that comprises three (3) sides, three (3) vertices and three (3) angles only.

<h3>What is a line segment?</h3>

A line segment can be defined as the part of a line in a geometric figure such as a triangle, circle, quadrilateral, etc., that is bounded by two (2) distinct points and it typically has a fixed length.

<h3>What is a perpendicular bisector?</h3>

A perpendicular bisector can be defined as a type of line that bisects (divides) a line segment exactly into two (2) halves and forms an angle of 90 degrees at the point of intersection.

In this scenario, we can reasonably infer that to divide the triangles into these regions, you should construct the <u>perpendicular bisector</u> of each segment. These perpendicular bisectors intersect and divide each triangle into three regions. The points in each region are those closest to the vertex in that <u>region</u>.

Read more on perpendicular bisectors here: brainly.com/question/27948960

#SPJ1

5 0

2 years ago

What is the next step you should take?<br> 1 + 18n = 33

Ivahew [28]

Answer:

You need to carry the one over by subtracting 1 from 33. The new equation will be 18n = 32

3 0

3 years ago

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Three women, Chantel, Marissa, and Qian, enjoy running laps around a circular track. Each women runs at a constant speed. It tak

lubasha [3.4K]

It takes 150 seconds for Qian to complete the track.

Let she runs the track in the clockwise direction.

In 60 seconds, she runs $\frac{60}{150}$ = $\frac{2}{5}$ th of the track.

Since she meets Marissa, who is running in the opposite (counter clockwise) direction in every 60 seconds, Marissa should have completed $\frac{3}{5}$ th of the track.

Chantel meets Marissa in every 300 seconds.

So, in 60 seconds, she advances Marissa by $\frac{1}{5}$ th of the track.

Hence, in 300 seconds, Qian, Marissa and Chantel all meets at the starting point.

ALITER;

Marissa meets Qian in every 60 seconds.

So, Marissa and Qian meet each other in 60th, 120th, 180th, 240th and 300th second.

But, it is given that Chantel meets Marissa in every 300 seconds.

So, in 300 seconds, Qian, Marissa and Chantel meet each other.

6 0

3 years ago

What can you say about the sum of consecutive odd numbers starting with 1? that is, evaluate 1, 1c3, 1c3c5, 1c3c5c7, and so on,

Mice21 [21]

Let us add consecutive odd numbers and try to find any relationship.

1. 1

2. 1+3 = 4 ( square of 2 i.e $2^{2}$ )

3. 1+3+5 = 9 ( $3^{2}$ )

4. 1+3+5+7 = 16 ( $4^{2}$ )

5. 1+3+5+7+9 = 25 ( $5^{2}$ )

6. 1+3+5+7+9+11 = 36 ( $6^{2}$ )

7. 1+3+5+7+9+11+13 = 49 ( $7^{2}$ )

If we notice, the sum of the consecutive odd integers in each case is equal to the square of the place where it lies. For example, the sum of numbers in seventh place is equal to $7^{2}$ . The sum of the numbers in the fifth line is equal to $5^{2}$ .

4 0

3 years ago