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I am Lyosha [343]
3 years ago
11

Solve the following and explain your steps. Leave your answer in base-exponent form. (3^-2*4^-5*5^0)^-3*(4^-4/3^3)*3^3 please st

ep by step!!!!
Mathematics
1 answer:
Naily [24]3 years ago
4 0

Answer:

\boxed{2^{\frac{802}{27}} \cdot 3^9}

Step-by-step explanation:

<u>I will try to give as many details as possible. </u>

First of all, I just would like to say:

\text{Use } \LaTeX !

Texting in Latex is much more clear and depending on the question, just writing down without it may be confusing or ambiguous. Be together with Latex! (*^U^)人(≧V≦*)/

$(3^{-2} \cdot 4^{-5} \cdot 5^0)^{-3} \cdot (4^{-\frac{4}{3^3} })\cdot 3^3$

Note that

\boxed{a^{-b} = \dfrac{1}{a^b}, a\neq 0 }

The denominator can't be 0 because it would be undefined.

So, we can solve the expression inside both parentheses.

\left(\dfrac{1}{3^2}  \cdot \dfrac{1}{4^5}  \cdot 5^0 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{3^3} } }\right)\cdot 3^3

Also,

\boxed{a^{0} = 1, a\neq 0 }

\left(\dfrac{1}{9}  \cdot \dfrac{1}{1024}  \cdot 1 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27

Note

\boxed{\dfrac{1}{a} \cdot \dfrac{1}{b}= \frac{1}{ab} , a, b \neq  0}

\left(\dfrac{1}{9216}   \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27

\left(\dfrac{1}{9216}   \right)^{-3} \cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)

\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)

\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)

Note

\boxed{\dfrac{1}{\dfrac{1}{a} }  = a}

9216^3\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)

\left(\dfrac{ 9216^3\cdot 27}{4^{\frac{4}{27} } }\right)

Once

9216=2^{10}\cdot 3^2 \implies  9216^3=2^{30}\cdot 3^6

\boxed{(a \cdot b)^n=a^n \cdot b^n}

And

$4^{\frac{4}{27}} = 2^{\frac{8}{27} $

We have

\left(\dfrac{ 2^{30} \cdot 3^6\cdot 27}{2^{\frac{8}{27} } }\right)

Also, once

\boxed{\dfrac{c^a}{c^b}=c^{a-b}}

2^{30-\frac{8}{27}} \cdot 3^6\cdot 27

As

30-\dfrac{8}{27} = \dfrac{30 \cdot 27}{27}-\dfrac{8}{27}  =\dfrac{802}{27}

2^{30-\frac{8}{27}} \cdot 3^6\cdot 27 = 2^{\frac{802}{27}} \cdot 3^6 \cdot 3^3

2^{\frac{802}{27}} \cdot 3^9

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My name is Ann [436]

Answer:

See Explanation.

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

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  • Left to Right

Equality Properties

  • Multiplication Property of Equality
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<u>Algebra I</u>

Slope Formula: \displaystyle m=\frac{y_2-y_1}{x_2-x_1}

Slope-Intercept Form: y = mx + b

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Linear Regression

Step-by-step explanation:

We can draw any best line of fit, as long as it is <em>reasonable</em> around the points that are given.

We can just take 2 points and use slope formula and Slope-Intercept Form to find the equation for the best line of fit.

Using Linear Regression, we can determine the <em>true</em> best line of fit using graphing utilities.

<u>Finding the best line of fit</u>

<em>Define 2 points</em>

Point (21600, 205)

Point (27000, 290)

<em>Find slope m</em>

  1. Substitute in point [SF]:                    \displaystyle m=\frac{290-205}{27000-21600}
  2. [Fraction] Subtract:                           \displaystyle m=\frac{85}{5400}
  3. [Fraction] Simplify:                            \displaystyle m=\frac{17}{1080}

<em>Find equation</em>

  1. Define equation [SIF]:                        \displaystyle y = \frac{17}{1080}x + b
  2. Substitute in point:                            \displaystyle 290 = \frac{17}{1080}(27000) + b
  3. Multiply:                                             \displaystyle 290 = 425 + b
  4. Isolate y-intercept <em>b</em>:                         \displaystyle -135 = b
  5. Rewrite:                                             \displaystyle b = -135
  6. Redefine equation:                           \displaystyle y = \frac{17}{1080}x - 135

Slope-Intercept Form tells us that our slope <em>m</em> = \displaystyle \frac{17}{1080} and our y-intercept \displaystyle b = -135.

Setting this as function f(x), we can see from the graph that it is extremely accurate (Blue line).

<u>Using Linear Regression</u>

Depending on the graphing calc you have, the steps may be different.

Using a graphing calc, we can use statistics and determine the <em>best</em> best line of fit.

When we determine the values, we should see that our equation would be g(x) (Green Line).

<em>Credit to Lauren for collabing w/ me in graphing.</em>

6 0
3 years ago
Using the weighted average approach to process costing, floridyne would use what number of equivalent units in 2019 to calculate
timofeeve [1]

Floridyne would use an equivalent unit labor of 166,340 unit to calculate the cost per equivalent unit for direct labor.

<h3>How do we get the equivalent unit labor?</h3>

Under weighted average, we do not make distinction between started and finished and just finished. Thus we work with finished and ending WIP only:

Finished         162,000

Ending - WIP    6,200 ending at 70% complete

Equivalent units for labor = Finished + Percentage of completion ending units

= 162,000 + 6,200 x 70%

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Therefore, he would use an equivalent unit labor of 166,340 unit to calculate the cost per equivalent unit for direct labor.

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