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2 years ago

13

You are buying potato chips at the grocery store. You have a manufacturer’s coupon for $1.00 off and the store is offering 20% o

ff if you buy 2 bags. How do you compute your final cost?

1 answer:

valkas [14]2 years ago

6 0

First find 10% then double subtract $1 and you'll get a final answer

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Find the missing variable. <br> Round to the nearest tenth.

Ksju [112]

Answer:340 or 5 depends how your using it

Step-by-step explanation:

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2 years ago

The graph of a line with the following slope and y-intercept

sweet [91]

First you grapgh 0,-3 then you follow the slope of going 4 up 5 to the right and contine up also on e-where it is 0,-3 you go down 4 and 5 to the left and contine that to make a straught line.

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2 years ago

There are 50 pennies in a roll. If you have 150 rolls of pennies, how many pennies do you have?

Y_Kistochka [10]

Answer: 7500

Step-by-step explanation:

multiply 150 by 50

8 0

2 years ago

Bryan jogged the same distance each day for 7 days. He ran a total of 22.4 miles. The equation 7d=22.4 can be used to find the d

Maru [420]

I hope this helps you

if he jogged 22.4 miles in 7 days

he jogged ? miles in 1 day

?.7=22.4

?=22.4/7

?=3.2

6 0

3 years ago

The mean number of daily surgeries at a local hospital is 6.2. Assume that surgeries are random, independent events. (a) The cou

Scilla [17]

Answer:

a) correct option is

Poisson distribution is 6.2 and standard deviation is 2.49

b) probability for only 2 or less than 2 surgeries in a given day is 0.0536

Step-by-step explanation:

Given data:

mean number is given as 6.2

correct option is

Poisson distribution is 6.2 and standard deviation is 2.49

we know that variance is given as $\sigma^2 = mean = 6.2$

hence, standard deviation is given as $\sqrt{6.2} = 2.48998$

thus standard deviation is 2.49

correct option is

Poisson distribution is 6.2 and standard deviation is 2.49

b) probability for only 2 or less than 2 surgeries in a given day is

$P(X \leq 2) = P(X =0) + P(X =1) + P(X =2)$

$= \frac{e^{-6.2} 6.2^0}{0!} +\frac{e^{-6.2} 6.2^1}{1!} +\frac{e^{-6.2} 6.2^2}{2!}$

= 0.002029 + 0.012582+ 0.039006

= 0.053617

= 0.0536

7 0

2 years ago