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charle [14.2K]
3 years ago
12

Let Y be a random variable with a density function given by

Mathematics
1 answer:
Neporo4naja [7]3 years ago
5 0

From the given density function we find the distribution function,

F_Y(y)=P(Y\le y)=\displaystyle\int_{-\infty}^y f_Y(t)\,\mathrm dt=\begin{cases}0&\text{for }y

(a)

F_{U_1}(u_1)=P(U_1\le u_1)=P(3Y\le u_1)=P\left(Y\le\dfrac{u_1}3\right)=F_Y\left(\dfrac{u_1}3\right)

\implies F_{U_1}(u_1)=\begin{cases}0&\text{for }u_1

\implies f_{U_1}(u_1)=\begin{cases}\frac{{u_1}^2}{18}&\text{for }-3\le u_1\le3\\0&\text{otherwise}\end{cases}

(b)

F_{U_2}(u_2)=P(3-Y\le u_2)=P(Y\ge3-u_2)=1-P(Y

\implies F_{U_2}(u_2)=\begin{cases}0&\text{for }u_2

\implies f_{U_2}(u_2)=\begin{cases}\frac32(u_2-3)^2&\text{for }2\le u_2\le4\\0&\text{otherwise}\end{cases}

(c)

F_{U_3}(u_3)=P(Y^2\le u_3)=P(-\sqrt{u_3}\le Y\le\sqrt{u_3})=F_Y(\sqrt{u_3})-F_y(\sqrt{u_3})

\implies F_{U_3}(u_3)=\begin{cases}0&\text{for }u_3

\implies f_{U_3}(u_3}=\begin{cases}\frac32\sqrt u&\text{for }0\le u\le1\\0&\text{otherwise}\end{cases}

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Please help
scoray [572]

Answer:

2/24 ft3

Step-by-step explanation: The formula for volume is the area of the base times the height.

1/8 x 2/3= 2/24  

It would be cubed though because your multiplying ft squared by ft



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2 years ago
Consider a nine -year moving average used to smooth a time series that was first recorded in 1961. a. Which year serves as the f
kirill [66]

Answer:

  a.  1965

  b.  8 years

Step-by-step explanation:

For answers to questions like these it can work to consider the smallest possible dataset.

<h3>Dataset</h3>

For our purpose, consider the 9 years/values to be averaged to be ...

  1, 2, 3, 4, 5, 6, 7, 8 ,9

<h3>Observations</h3>

a. The center value of the data set is 5. Its number is 5-1=4 more than the first one.

The first centered value is from the year 1961 +4 = 1965.

b. The 4 values at the beginning, and the 4 values at the end do not have a corresponding "average" value. That is, 4+4 = 8 values in the series are lost with respect to the number of average values.

8 years of values are lost.

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2 years ago
What is an equation of the line that passes through the points (1, -7) and (-4, 8)?
melomori [17]
<h2>Answer:    y + 7  =  -3 (x - 1)</h2>

Step-by-step explanation:

The slope of the line (m) = (y₂ - y₁) ÷ (x₂ - x₁)  

                                       

                                          =  (- 7 - 8) ÷ ( 1 - (- 4))

                                         =    - 15  ÷  5

                                         =  - 3

We can now use the point-slope form to write the equation for this line:

        y - y₁ = m(x - x₁) where (x₁ , y₁) = (1, -7)

             y - (-7) =  -3 ( x  -  1)

              y + 7  =  -3 (x - 1)

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