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marshall27 [118]
4 years ago
14

Elvira is 5 years older than Morton. Morton is twice as old as Michelle. The combined total of their ages is 85. How old is Mort

on?
Mathematics
2 answers:
LiRa [457]4 years ago
8 0

Elvira (e) is 5 years older than Morton (m)

e = m + 5

Morton (m) is twice as old as Michelle (c)

m = 2c

The combined total of their ages is 85

e + m + c = 85

We want m at the end so let's write everything in terms of m.

e = m + 5

c = m/2

85 = e + m + c = m+5 + m + m/2 = 5 + (5/2) m

m = (2/5) (85 - 5) = 32

Answer: 32 years old

Check:

That makes Elvira 37 and Michele 16, total 32+37+16=85, good


melisa1 [442]4 years ago
8 0

Answer:-  Elvira is 37, Morton is 32 and Michelle is 16 years old.

Create some  equations:-

Let Elvira's age be e , Morton's m years and Michelle's age = n years.

e + m + n = 85........... (1)

e - m = 5......................(2)

n = m/2

Substitute for n in the equation (1)

e + (3/2)m     = 85........... (3)

Subtract equation (2) from equation 3:-

5/2 m = 80

m =  32

So e = m +5 = 37

and n = 32/2 = 16



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Step-by-step explanation:

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Answer:

4p3 + 6p2 - 8p - 7

Step-by-step explanation:

Reformatting the input :

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Equation at the end of step 1

 (((4 • (p3)) +  (2•3p2)) -  7) -  8p

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Equation at the end of step

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Checking for a perfect cube

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Trying to factor by pulling out :

3.2      Factoring:  4p3+6p2-8p-7

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1:  -8p-7

Group 2:  4p3+6p2

Pull out from each group separately :

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3.3    Find roots (zeroes) of :       F(p) = 4p3+6p2-8p-7

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Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers  p  which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number  P/Q   then  P  is a factor of the Trailing Constant and  Q  is a factor of the Leading Coefficient

In this case, the Leading Coefficient is  4  and the Trailing Constant is  -7.

The factor(s) are:

of the Leading Coefficient :  1,2 ,4

of the Trailing Constant :  1 ,7

Let us test ....

  P    Q    P/Q    F(P/Q)     Divisor

     -1       1        -1.00        3.00    

     -1       2        -0.50        -2.00    

     -1       4        -0.25        -4.69    

     -7       1        -7.00       -1029.00    

     -7       2        -3.50        -77.00    

     -7       4        -1.75        3.94    

     1       1        1.00        -5.00    

     1       2        0.50        -9.00    

     1       4        0.25        -8.56    

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     7       2        3.50        210.00    

     7       4        1.75        18.81    

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