Answer:
Two possible lengths for the legs A and B are:
B = 1cm
A = 14.97cm
Or:
B = 9cm
A = 12cm
Step-by-step explanation:
For a triangle rectangle, Pythagorean's theorem says that the sum of the squares of the cathetus is equal to the hypotenuse squared.
Then if the two legs of the triangle are A and B, and the hypotenuse is H, we have:
A^2 + B^2 = H^2
If we know that H = 15cm, then:
A^2 + B^2 = (15cm)^2
Now, let's isolate one of the legs:
A = √( (15cm)^2 - B^2)
Now we can just input different values of B there, and then solve the value for the other leg.
Then if we have:
B = 1cm
A = √( (15cm)^2 - (1cm)^2) = 14.97
Then we could have:
B = 1cm
A = 14.97cm
Now let's try with another value of B:
if B = 9cm, then:
A = √( (15cm)^2 - (9cm)^2) = 12 cm
Then we could have:
B = 9cm
A = 12cm
So we just found two possible lengths for the two legs of the triangle.
Answer:
6x^2 - 10x inches ^2
Step-by-step explanation:
The area of a rectangle is
A = l*w
= (3x-5) * (2x)
= 6x^2 - 10x
2) -88, -45, 5, 40
4) -45, -31, 20, 49
6) -74, -63, -45, 38
8) 18, 27, 27, 58
10) -60, -49, -40, 9
12) -45, -18, 80, 82
The bigger negative numbers are the least because negative numbers work the opposite way around of positive numbers. :)
Answer:
C (x ≥ -6)
Step-by-step explanation:
<u>Algebraic:</u>
The domain of 
is 
. When transformed 6 units to the left, it becomes 
<u>Graphically:</u>
As shown in the attached graph, .
Answer is 0.124. I have to right more characters
