<em>The word usage in last sentence of the question is not well presented. However, I can understand that you intend to solve for the width of the park</em>
Answer:
Step-by-step explanation:
Given
Required
Determine the Width
For a rectangle:
Substitute for Area and Length
Multiply both sides by 
All you need to do is subtract.
1-5 is -4. 1-3 is -2 thus (-4,-2)
4-5=-1. 2-3=-1 thus (-1,-1) at this point there is only one option left
B Is the answer
Answer:
Step-by-step explanation:
(-3x + 2)(45x + 21) + (-4x + 25) = 50
-135x^2 - 63x + 90x + 42 - 4x + 25 = 50
-135x^2 + 23x + 67 = 50
-135x^2 + 23x + 67 - 50 = 0
-135x^2 + 23x + 17 = 0
quadratic formula : x = (-b ± √b^2 - 4ac)/2a
a = -135, b = 23, c = 17
x = -23 ± √23^2 - 4(-135)(17) / (2(-135)
x = (-23 ±√9709 )/ -270
x = 23/270 ± 1 / 270√9709/270
x = 0.4501 or x = - 0.2798 <=== these answers are rounded
The answer is 2/3 in lowest terms.
In order for the triangle to be isosceles, we have to set two lengths of the triangle equal to each other.
Let's take the lengths 5x-12 and x+20 and set them equal to each other.
5x - 12 = x + 20
Combine like terms by moving them over to their respective sides.
Subtract x from both sides of the equation.
4x - 12 = 20
Add 12 to both sides of the equation.
4x = 32
Divide both sides by 4.
x = 8
Check your answer by substituting.
5x - 12 = x + 20
5(8) - 12 = 8 + 20
40 - 12 = 28
28 = 28
Solution: x = 8
