Hello :
the normal vector of the plane is : d' = [4,-1,5]...(vector perpendicular to the plane)<span>
d </span><span>⊥ d' because : (4)(2)+(-1)(3)+(5)(1)=0
</span>the line is perpendicular to the plane .
Yo sup??
To solve this question we have to apply trigonometric ratios
sin31=UT/TV
TV=UT/sin31
=7.76
=7.8
Hope this helps.
Each book costs $34 for this problem you need to first subtract 18 from 324 which gets you 306 then divide 306 by 9 and you get 34
What? You bought a call with options, and 50 lightning??
Answer:
x3
Step-by-step explanation:
