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3 years ago

Find the value of each trigonometric ratio!! Pls hurry!!!

Mathematics

1 answer:

Likurg_2 [28]3 years ago

4 0

tan A is 4/3

use sohcahtoa

Angle a is 53.130 if you need it

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Need help with this ASAP

Mariana [72]

Answer:

Sequence: 13, 20, 27

Rule: Tn = 7n + 6

Step-by-step explanation:

The 3 other numbers that can form an arithmetic progression is 13, 20, 27...

The nth term of an arithmetic progression is expressed as;

Tn = a + (n-1)d

a is the first term = 13

n is the number of terms

d is the common difference = 20 - 13 = 27 - 20

d = 7

Substitute

Tn = 13 + (n-1)(7)

Tn = 13 + 7n - 7

Tn = 7n+13-7

Tn = 7n + 6

This gives the required rule

5 0

3 years ago

A student has $5.00 to spend on a poster, paint, and stickers. The total cost for the

babunello [35]

Answer:

2.8+.55x=5 x=4

Step-by-step explanation:

5-2.8=2.2

2.2/.55=4

4 0

2 years ago

Which of the is the same as2.3×10^3

dalvyx [7]

2300 you mover the decimal over 3 spaces

7 0

3 years ago

Read 2 more answers

Problem Solve 88 – (–35)

Rasek [7]

Subtract negative = add
88 + 35 = 123
The solution is 123

7 0

2 years ago

Read 2 more answers

A bin is constructed from sheet metal with a square base and 4 equal rectangular sides. if the bin is constructed from 48 square

kondaur [170]

This is a problem of maxima and minima using derivative.

In the figure shown below we have the representation of this problem, so we know that the base of this bin is square. We also know that there are four square rectangles sides. This bin is a cube, therefore the volume is:

V = length x width x height

That is:

$V = xxy = x^{2}y$

We also know that the <span>bin is constructed from 48 square feet of sheet metal, s</span>o:

Surface area of the square base = $x^{2}$

Surface area of the rectangular sides = $4xy$

Therefore, the total area of the cube is:

$A = 48 ft^{2} = x^{2} + 4xy$

Isolating the variable y in terms of x:

$y = \frac{48- x^{2} }{4x}$

Substituting this value in V:

$V = x^{2}( \frac{48- x^{2} }{x}) = 48x- x^{3}$

Getting the derivative and finding the maxima. This happens when the derivative is equal to zero:

$\frac{dv}{dx} = 48-3x^{2} =0$

Solving for x:

$x = \sqrt{\frac{48}{3}} = \sqrt{16} = 4$

Solving for y:

$y = \frac{48- 4^{2} }{(4)(4)} = 2$

Then, <span>the dimensions of the largest volume of such a bin is:
</span>
Length = 4 ft
Width = 4 ft
Height = 2 ft

And its volume is:

$V = (4^{2} )(2) = 32 ft^{3}$

8 0

2 years ago