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masha68 [24]
3 years ago
6

you are in the research and development department at Jiffy Pop. the company is trying to come up with the new and improved popc

orn box to produce for movie theaters. The goal is to create a box with a with two in less than the length and width the height 5 in greater than the length the volume of the Box must be 24 cubic inches in order to hold enough popcorn.
Mathematics
1 answer:
Monica [59]3 years ago
7 0
Let L be the length of the box that the company aims to manufacture. With this representation, the width of the box is equal to L - 2 and the height is equal to L + 5. The volume of the box is equal to the product of the length, width, and height. That is,
                          A = L x (L - 2) x (L + 5) = 24

The value of L from the equation is 3 inches. 

The dimension of the box are as follow: 
length = L = 3 inches
width = L - 2 = 1 inch
height = L + 5 = 8 inches

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For what Value of X is ABC~ DEF?​
Zina [86]

Answer:

The answer to the question is A

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3 years ago
A normal distribution has a mean of 137 and a standard deviation of 7. Find the z-score for a data value of 121. Incorrect Round
Neko [114]

Answer:

The z-score for a data value of 121 is -2.29.

Step-by-step explanation:

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 137, \sigma = 7

Find the z-score for a data value of 121.

This is Z when X = 121. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{121 - 137}{7}

Z = -2.29

The z-score for a data value of 121 is -2.29.

4 0
3 years ago
Read 2 more answers
Please help! This is due in 3 minutes!
Alina [70]
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3 years ago
In a random sample of 30 people who rode a roller coaster one day, the mean wait time is 46.7 minutes with a standard deviation
Rainbow [258]

Answer: C. (29,\ 37.8)

Step-by-step explanation:

The confidence interval for difference of two population mean is given by :-

\overline{x}_1-\overline{x}_2\pm z_{\alpha/2}\sqrt{\dfrac{s_1^2}{n_1}+\dfrac{s_2^2}{n_2}}

Given : Level of significance : 1-\alpha:0.99

Then , significance level : \alpha: 1-0.99=0.01

Critical value : z_{\alpha/2}=z_{0.005}=2.576

n_1=30\ ;\ n_2=50\\\\\overline{x}_1=46.7\ ;\ \overline{x}_2=13.3\\\\s_1=9.2\ ;\ s_2=1.9

46.7-13.3\pm(2.576)\sqrt{\dfrac{9.2^2}{30}+\dfrac{1.9^2}{50}}\approx33.4\pm4.38=(29.02\ ,37.78)\approx(29,\ 37.8)

Hence,  a 99% confidence interval for the difference between the mean wait times of everyone who rode both rides (29,\ 37.8)

5 0
3 years ago
Can u change 28/140 into a percent
Anton [14]

Answer:

2%

Step-by-step explanation:

28/140=0.2

5 0
3 years ago
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