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3 years ago

Find the least number of three digit which is a perfect square.

Mathematics

1 answer:

Marizza181 [45]3 years ago

4 0

$30^2=900\\31^2=961\\32^2=1024\\\\Answer:\boxed{961}$

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Hi can anyone help me do this question,I will mark brainlest.

saul85 [17]

Answer:

11. 40.5

12. 84

Step-by-step explanation:

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3 years ago

PLEASE HELP ME I PUT A PICTURE WITH ALL POSSIBLE ANSWERS what is -22.2 x (-6.1)?

Montano1993 [528]

Answer:

Step-by-step explanation:

You just need to calculate it as usual. Might as well do in fraction form for clearer understandings

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3 years ago

Read 2 more answers

You buy 1.75 pounds of apples and 2.05 pounds of oranges. Apples and oranges sell for the same price per pound. The total cost,

dlinn [17]

Answer:

$1.75c+2.05c=4.18\\\\Per\ pound\ cost=c=\$1.1$

Step-by-step explanation:

$Cost\ of\ per\ pound\ apple=Cost\ of\ per\ pound\ oranger=c\\\\$

Cost of Apples:

$Amount\ of\ apples=1.75\ pounds\\\\Cost\ of\ apples=Amount\times per\ pound\ cost\\\\Cost\ of\ apples=1.75\times c\\\\Cost\ of\ apples=1.75c$

Cost of oranges:

$Amount\ of\ oranges=2.05\ pounds\\\\Cost\ of\ oranges=Amount\times per\ pound\ cost\\\\Cost\ of\ oranges=2.05\times c\\\\Cost\ of\ oranges=2.05c$

Total cost:

$Total\ cost\ of\ fruits=cost\ of\ apple+cost\ of\ oranges\\\\Total\ cost\ of\ fruits=1.75c+2.05c\\\\After\ coupon\ cost=\$ 3.43\\\\ Original\ cost=After\ coupon\ cost+coupon\ amount\\\\ Original\ cost=3.43+0.75=4.18$

$1.75c+2.05c=4.18\\\\3.8c=4.18\\\\c=\frac{4.18}{3.8}\\\\c=1.1\\\\Per\ pound\ cost\ of\ fruits=\$1.1$

4 0

3 years ago

The equation giving a family of ellipsoids is u = (x^2)/(a^2) + (y^2)/(b^2) + (z^2)/(c^2) . Find the unit vector normal to each

Fynjy0 [20]

Answer:

$\hat{n}\ =\ \ \dfrac{\dfrac{x}{a^2}\hat{i}+\ \dfrac{y}{b^2}\hat{j}+\ \dfrac{z}{c^2}\hat{k}}{\sqrt{(\dfrac{x}{a^2})^2+(\dfrac{y}{b^2})^2+(\dfrac{z}{c^2})^2}}$

Step-by-step explanation:

Given equation of ellipsoids,

$u\ =\ \dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}+\dfrac{z^2}{c^2}$

The vector normal to the given equation of ellipsoid will be given by

$\vec{n}\ =\textrm{gradient of u}$

$=\bigtriangledown u$

$=\ (\dfrac{\partial{}}{\partial{x}}\hat{i}+ \dfrac{\partial{}}{\partial{y}}\hat{j}+ \dfrac{\partial{}}{\partial{z}}\hat{k})(\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}+\dfrac{z^2}{c^2})$

$=\ \dfrac{\partial{(\dfrac{x^2}{a^2})}}{\partial{x}}\hat{i}+\dfrac{\partial{(\dfrac{y^2}{b^2})}}{\partial{y}}\hat{j}+\dfrac{\partial{(\dfrac{z^2}{c^2})}}{\partial{z}}\hat{k}$

$=\ \dfrac{2x}{a^2}\hat{i}+\ \dfrac{2y}{b^2}\hat{j}+\ \dfrac{2z}{c^2}\hat{k}$

Hence, the unit normal vector can be given by,

$\hat{n}\ =\ \dfrac{\vec{n}}{\left|\vec{n}\right|}$

$=\ \dfrac{\dfrac{2x}{a^2}\hat{i}+\ \dfrac{2y}{b^2}\hat{j}+\ \dfrac{2z}{c^2}\hat{k}}{\sqrt{(\dfrac{2x}{a^2})^2+(\dfrac{2y}{b^2})^2+(\dfrac{2z}{c^2})^2}}$

$=\ \dfrac{\dfrac{x}{a^2}\hat{i}+\ \dfrac{y}{b^2}\hat{j}+\ \dfrac{z}{c^2}\hat{k}}{\sqrt{(\dfrac{x}{a^2})^2+(\dfrac{y}{b^2})^2+(\dfrac{z}{c^2})^2}}$

Hence, the unit vector normal to each point of the given ellipsoid surface is

$\hat{n}\ =\ \ \dfrac{\dfrac{x}{a^2}\hat{i}+\ \dfrac{y}{b^2}\hat{j}+\ \dfrac{z}{c^2}\hat{k}}{\sqrt{(\dfrac{x}{a^2})^2+(\dfrac{y}{b^2})^2+(\dfrac{z}{c^2})^2}}$

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3 years ago

Find the value of g(5).<br><br> g(x) = (x – 3)(x + 1)

liberstina [14]

Answer:

Step-by-step explanation:

Exponential functions have a horizontal asymptote. The equation of the horizontal asymptote is

Horizontal Asymptote:

5 0

3 years ago