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3 years ago

Find the least number of three digit which is a perfect square.

Mathematics

1 answer:

Marizza181 [45]3 years ago

4 0

$30^2=900\\31^2=961\\32^2=1024\\\\Answer:\boxed{961}$

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Is it true or false that the middle term of a perfect square trinomial is equal to 2 × √(first term) × √(last term)?

FinnZ [79.3K]

False, because it's equal to 2 × first term × last term

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3 years ago

Given a sphere with a radius of 2 cm, find its volume to the nearest whole

Anton [14]

Answer: 34

Step-by-step explanation:

$V=\frac{4}{3}(\pi)(2^{3}) \approx \boxed{34}$

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2 years ago

Simplify -3p - 2m + 8p - 7m

Nadya [2.5K]

After you combine like terms you will get 5p - 9m.

-3p + 8p is the same thing as 8p - 3, so you get 5p.
-2m + (-7m) is -9m

-3p and 8p are like terms.
-2m and -7m are also like terms.

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3 years ago

X/2+x/3=3/4<br> Solve for x

hodyreva [135]

Answer:

x= 9/10

Step-by-step explanation:

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3 years ago

Find the center of mass of the wire that lies along the curve r and has density =4(1 sin4tcos4t)

dolphi86 [110]

The mass of the wire is found to be 40π√2 units.

To calculate the mass of the wire which runs along the curve r ( t ) with the density function δ=5.

The general formula is,

Mass = $\int_a^b \delta\left|r^{\prime}(t)\right| d t$

To find, we must differentiate this same given curve r ( t ) with respect to t to estimate |r'(t)|.

The given integration limits in this case are a = 0, b = 2π.

Now, as per the question;

The equation of the curve is given as;

r(t) = (4cost)i + (4sint)j + 4tk

Now, differentiate this same given curve r ( t ) with respect to t.

$\begin{aligned}\left|r^{\prime}(t)\right| &=\sqrt{(-4 \sin t)^2+(4 \cos t)^2+4^2} \\&=\sqrt{16 \sin ^2 t+16 \cos ^2 t+16} \\&=\sqrt{16\left(\sin t^2+\cos ^2 t\right)+16}\end{aligned}$

Further simplifying;

$\begin{aligned}&=\sqrt{16(1)+16} \\&=\sqrt{16+16} \\&=\sqrt{32} \\\left|r^{\prime}(t)\right| &=4 \sqrt{2}\end{aligned}$

Now, use integration to find the mass of the wire;

$\begin{aligned}&=\int_a^b \delta\left|r^{\prime}(t)\right| d t \\&=\int_0^{2 \pi} 54 \sqrt{2} d t \\&=20 \sqrt{2} \int_0^{2 \pi} d t \\&=20 \sqrt{2}[t]_0^{2 \pi} \\&=20 \sqrt{2}[2 \pi-0] \\&=40 \pi \sqrt{2}\end{aligned}$

Therefore, the mass of the wire is estimated as 40π√2 units.

To know more about density function, here

brainly.com/question/27846146

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The complete question is-

Find the mass of the wire that lies along the curve r and has density δ.

r(t) = (4cost)i + (4sint)j + 4tk, 0≤t≤2π; δ=5

5 0

1 year ago