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vampirchik [111]
3 years ago
9

What is the sum of the series? Write in expanded form making sure to show all steps used to find the sum

Mathematics
2 answers:
Marina86 [1]3 years ago
6 0

Answer: -16

Step-by-step explanation:

pantera1 [17]3 years ago
3 0

Answer:

-16

Step-by-step explanation:

k = 3

-2(3) + 5 = -1

k = 4

-2(4) + 5 = -3

k = 5

-2(5) + 5 = -5

k = 6

-2(6) + 5 = -7

(-1) + (-3) + (-5) + (-7)

= -16

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7 0
3 years ago
1
FromTheMoon [43]

Answer:

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Step-by-step explanation:

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4 0
2 years ago
Read 2 more answers
This 1 seems really complicated
Fofino [41]
The solution to this system set is:  "x = 4" , "y = 0" ;  or write as:  [4, 0] .
________________________________________________________
Given: 
________________________________________________________
 y = - 4x + 16 ; 

 4y − x + 4 = 0 ;
________________________________________________________
"Solve the system using substitution" .
________________________________________________________
First, let us simplify the second equation given, to get rid of the "0" ; 

→  4y − x + 4 = 0 ; 

Subtract "4" from each side of the equation ; 

→  4y − x + 4 − 4 = 0 − 4 ;

→  4y − x = -4 ;
________________________________________________________
So, we can now rewrite the two (2) equations in the given system:
________________________________________________________
   
y = - 4x + 16 ;   ===> Refer to this as "Equation 1" ; 

4y − x =  -4 ;     ===> Refer to this as "Equation 2" ; 
________________________________________________________
Solve for "x" and "y" ;  using "substitution" :
________________________________________________________
We are given, as "Equation 1" ;

→  " y = - 4x + 16 " ;
_______________________________________________________
→  Plug in this value for [all of] the value[s] for "y" into {"Equation 2"} ;

       to solve for "x" ;   as follows:
_______________________________________________________
Note:  "Equation 2" :

     →  " 4y − x =  - 4 " ; 
_________________________________________________
Substitute the value for "y" {i.e., the value provided for "y";  in "Equation 1}" ;
for into the this [rewritten version of] "Equation 2" ;
→ and "rewrite the equation" ;

→   as follows:  
_________________________________________________

→   " 4 (-4x + 16) − x = -4 " ;
_________________________________________________
Note the "distributive property" of multiplication :
_________________________________________________

   a(b + c)  = ab + ac ;   AND: 

   a(b − c) = ab <span>− ac .
_________________________________________________
As such:

We have:  
</span>
→   " 4 (-4x + 16) − x = - 4 " ;
_________________________________________________
AND:

→    "4 (-4x + 16) "  =  (4* -4x) + (4 *16)  =  " -16x + 64 " ;
_________________________________________________
Now, we can write the entire equation:

→  " -16x + 64 − x = - 4 " ; 

Note:  " - 16x − x =  -16x − 1x = -17x " ; 

→  " -17x + 64 = - 4 " ;   Solve for "x" ; 

Subtract "64" from EACH SIDE of the equation:

→  " -17x + 64 − 64 = - 4 − 64 " ;   

to get:  

→  " -17x = -68 " ;

Divide EACH side of the equation by "-17" ; 
   to isolate "x" on one side of the equation; & to solve for "x" ; 

→  -17x / -17 = -68/ -17 ; 

to get:  

→  x = 4  ;
______________________________________
Now, Plug this value for "x" ; into "{Equation 1"} ; 

which is:  " y = -4x + 16" ; to solve for "y".
______________________________________

→  y = -4(4) + 16 ; 

        = -16 + 16 ; 

→ y = 0 .
_________________________________________________________
The solution to this system set is:  "x = 4" , "y = 0" ;  or write as:  [4, 0] .
_________________________________________________________
Now, let us check our answers—as directed in this very question itself ; 
_________________________________________________________
→  Given the TWO (2) originally given equations in the system of equation; as they were originally rewitten; 

→  Let us check;  

→  For EACH of these 2 (TWO) equations;  do these two equations hold true {i.e. do EACH SIDE of these equations have equal values on each side} ; when we "plug in" our obtained values of "4" (for "x") ; and "0" for "y" ??? ; 

→ Consider the first equation given in our problem, as originally written in the system of equations:

→  " y = - 4x + 16 " ;    

→ Substitute:  "4" for "x" and "0" for "y" ;  When done, are both sides equal?

→  "0 = ?  -4(4) + 16 " ?? ;   →  "0 = ? -16 + 16 ?? " ;  →  Yes!  ;

 {Actually, that is how we obtained our value for "y" initially.}.

→ Now, let us check the other equation given—as originally written in this very question:

→  " 4y − x + 4 = ?? 0 ??? " ;

→ Let us "plug in" our obtained values into the equation;

 {that is:  "4" for the "x-value" ; & "0" for the "y-value" ;  

→  to see if the "other side of the equation" {i.e., the "right-hand side"} holds true {i.e., in the case of this very equation—is equal to "0".}.

→    " 4(0)  −  4 + 4 = ? 0 ?? " ;

      →  " 0  −  4  + 4 = ? 0 ?? " ;

      →  " - 4  + 4 = ? 0 ?? " ;  Yes!
_____________________________________________________
→  As such, from "checking [our] answer (obtained values)" , we can be reasonably certain that our answer [obtained values] :
_____________________________________________________
→   "x = 4" and "y = 0" ;  or; write as:  [0, 4]  ;  are correct.
_____________________________________________________
Hope this lenghty explanation is of help!  Best wishes!
_____________________________________________________
7 0
3 years ago
Suppose that in a certain chemical process the reaction time y (hr) is related to the temperature (°F) in the chamber in which t
Svetllana [295]

Answer:

The expected change in reaction time for a 1°F increase in temperature is 4.39 hours.

The expected change in reaction time for a 8°F increase in temperature is 4.32 hours.

Step-by-step explanation:

The simple linear regression line is used to determine the changes in the dependent variables when the independent variable is changed.

The general form of the simple linear regression line is:

y=\alpha +\beta x

The simple linear regression model for the reaction time of a certain chemical process based on the temperature (°F) in the chamber in which the reaction takes place is:

y=4.40-0.01\ x

Here,

<em>y</em> = reaction time (in hours)

<em>x</em> = temperature (°F)

Compute the expected change in reaction time for a 1°F increase in temperature as follows:

y=4.40-0.01\ (1^{\text{o}})

  =4.40-0.01\\=4.39\ \text{hours}

The expected change in reaction time for a 1°F increase in temperature is 4.39 hours.

Compute the expected change in reaction time for a 8°F increase in temperature as follows:

y=4.40-0.01\ (8^{\text{o}})

  =4.40-0.08\\=4.32\ \text{hours}

The expected change in reaction time for a 8°F increase in temperature is 4.32 hours.

7 0
3 years ago
What’s the equation of the line that be that passes through (4,2) and is parallel to the line y=2x-1
podryga [215]

y=mx+b

because the y=2x-1, so m=2

because we know (4.2), so we can bring it in to the function:

2=2x4+b

2=8+b

b=-6

So the other one is: y=2x-6

in other way it's 2x-y=6

Which means the answer is B.

8 0
3 years ago
Read 2 more answers
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