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BlackZzzverrR [31]
3 years ago
6

Explain mitosis and meiosis in your own words.

Chemistry
1 answer:
LuckyWell [14K]3 years ago
4 0
I always remembered the differences by Mitosis sounds like My Toes Is. Which means its body cells reproducing. 
And Meiosis is My overies. Which is sex cells reproducing. 

Mitosis - The body cell's nucleus makes a copy of its chromosomes. The Chromotids are then pulled to the poles of the cell and split in half, the cell then divides in half into two new cells. Each cell has one pair of chromosomes each.

Meiosis - The sex cells nucleus makes a copy of each chromosome same as before. But then the similar chromosomes group up and swap parts with each other. Making completely new chromosomes. They then split in half again, making two new cells with two different pairs of chromosomes. Which then split apart Once more creating 4 new cells (From the original one) Each with completely random chromosomes.
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Answer:

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2 years ago
What is the final temperature of the solution formed when 1.52 g of NaOH is added to 35.5 g of water at 20.1 °C in a calorimeter
Inessa [10]

Answer : The final temperature of the solution in the calorimeter is, 31.0^oC

Explanation :

First we have to calculate the heat produced.

\Delta H=\frac{q}{n}

where,

\Delta H = enthalpy change = -44.5 kJ/mol

q = heat released = ?

m = mass of NaOH = 1.52 g

Molar mass of NaOH = 40 g/mol

\text{Moles of }NaOH=\frac{\text{Mass of }NaOH}{\text{Molar mass of }NaOH}=\frac{1.52g}{40g/mole}=0.038mole

Now put all the given values in the above formula, we get:

44.5kJ/mol=\frac{q}{0.038mol}

q=1.691kJ

Now we have to calculate the final temperature of solution in the calorimeter.

q=m\times c\times (T_2-T_1)

where,

q = heat produced = 1.691 kJ = 1691 J

m = mass of solution = 1.52 + 35.5 = 37.02 g

c = specific heat capacity of water = 4.18J/g^oC

T_1 = initial temperature = 20.1^oC

T_2 = final temperature = ?

Now put all the given values in the above formula, we get:

1691J=37.02g\times 4.18J/g^oC\times (T_2-20.1)

T_2=31.0^oC

Thus, the final temperature of the solution in the calorimeter is, 31.0^oC

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