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BlackZzzverrR [31]
4 years ago
6

Explain mitosis and meiosis in your own words.

Chemistry
1 answer:
LuckyWell [14K]4 years ago
4 0
I always remembered the differences by Mitosis sounds like My Toes Is. Which means its body cells reproducing. 
And Meiosis is My overies. Which is sex cells reproducing. 

Mitosis - The body cell's nucleus makes a copy of its chromosomes. The Chromotids are then pulled to the poles of the cell and split in half, the cell then divides in half into two new cells. Each cell has one pair of chromosomes each.

Meiosis - The sex cells nucleus makes a copy of each chromosome same as before. But then the similar chromosomes group up and swap parts with each other. Making completely new chromosomes. They then split in half again, making two new cells with two different pairs of chromosomes. Which then split apart Once more creating 4 new cells (From the original one) Each with completely random chromosomes.
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In addition to canyons,what other kinds of geologic formations might separate similar organisms
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A mountain range prevents two types of goat from mating, causing the gene pool to become less varied.<span>

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7 0
3 years ago
In the formula for carbon tetrahydride, CH4, the percent composition of all elements is:
creativ13 [48]
C%=12/16*100=3/4*100=75%
H%=25%
8 0
3 years ago
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What does variable mean in a science project.
Paul [167]
Well, an independent variable ids the thing that  stays the same and a dependent variable is the thing that changes.

6 0
4 years ago
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Find the empirical formula of the compound ribose, a simple sugar often used as a nutritional supplement. A 14.229 g sample of r
MakcuM [25]

Answer:

CH2O

Explanation:

Firstly, we need to convert the masses of the elements to percentage compositions. This can be done by placing the mass of each element over the total mass multiplied by 100% . We can start with carbon.

C = 5.692/14.229 * 100 = 40%

O = 7.582/14.229 * 100 = 53.29%

H = 0.955/14.229 * 100 = 6.71%

We then proceed to divide each percentage composition by their atomic mass of 12, 16 and 1 respectively.

C = 40/12 = 3.333

O = 53.29/16 = 3.33

H = 6.71/2 = 6.71

Dividing by the smaller value which is 3.33

C = 3.33/3.33 = 1

O = 3.33/3.33= 1

H = 6.71/3.33 = 2

The empirical formula of the compound ribose is CH2O

6 0
3 years ago
Read 2 more answers
A 0.1326 g sample of magnesium was burned in an oxygen bomb calorimeter. the total heat capacity of the calorimeter plus water w
Sladkaya [172]

Answer: Th enthalpy of combustion for the given reaction is 594.244 kJ/mol

Explanation: Enthalpy of combustion is defined as the decomposition of a substance in the presence of oxygen gas.

W are given a chemical reaction:

Mg(s)+\frac{1}{2}O_2(g)\rightarrow MgO(s)

c=5760J/^oC

\Delta T=0.570^oC

To calculate the enthalpy change, we use the formula:

\Delta H=c\Delta T\\\\\Delta H=5760J/^oC\times 0.570^oC=3283.2J

This is the amount of energy released when 0.1326 grams of sample was burned.

So, energy released when 1 gram of sample was burned is = \frac{3283.2J}{0.1326g}=24760.181J/g

Energy 1 mole of magnesium is being combusted, so to calculate the energy released when 1 mole of magnesium ( that is 24 g/mol of magnesium) is being combusted will be:

\Delta H=24760.181J/g\times 24g/mol\\\\\Delta H=594244.3J/mol\\\\\Delta H=594.244kJ/mol

4 0
3 years ago
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