464 g radioisotope was present when the sample was put in storage
<h3>Further explanation</h3>
Given
Sample waste of Co-60 = 14.5 g
26.5 years in storage
Required
Initial sample
Solution
General formulas used in decay:

t = duration of decay
t 1/2 = half-life
N₀ = the number of initial radioactive atoms
Nt = the number of radioactive atoms left after decaying during T time
Half-life of Co-60 = 5.3 years
Input the value :

Hello
the answer is 43.129310000000004
Have a nice day
2.91 is the amount of atoms
Answer:
May you post a picture for us to understand?
Answer:
The answer to your question is: Cp = 0.129 J/g°C
Explanation:
Data
mass = 955 g of tungsten
T1 = 18°C
T2 = 100°C
Q = 10180 Joules
Cp = ?
Formula
Q = mCpΔT
Clear Cp from the equation
Cp = Q / mΔT
Substitution
Cp = 10180 / (955(100-18))
Cp = 10180 / (955(82))
Cp = 10180 / 78310
Cp = 0.129 J/g°C