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erik [133]
3 years ago
10

At what temperature does the solid start melting? -20°C 0°C 20°C 80°C

Chemistry
2 answers:
Paraphin [41]3 years ago
8 0

Answer:

0

Explanation:

Because I need please points help and thank me

Bond [772]3 years ago
3 0

Answer:

The correct answer is 0°C

Explanation:

In the case of water, the melting point occurs at 0 ° C, in which the solid becomes liquid.

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1.79 moles

Explanation:

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3 0
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Determine the composition of each phase in a cu-40% ni alloy at 1300c,
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To be able to answer this, you need to have a phase diagram of Cu-Ni alloy. Create a vertical line along 40% in the x-axis. Then, create a horizontal line along the temperature at 1,300°C. The intersection lies outside of the α-L boundary. <em>Therefore, the system consist solely of the L-phase: 100% L.</em>

4 0
3 years ago
The age of fossils can sometimes be determined by radiometric dating, which is based on the constant rate of decay of radioactiv
True [87]
The age of the fossil given the present amount of Carbon-14 is given in the equation,
                               A(t) = A(o)(0.5)^t/h
where A(t) is the current amount, A(o) is the initial amount, t is time and h is the half-life. Substituting the known values to the equation,
                       A(t) / A(o) = 0.125 = (0.5)^(t/5730)
The value of t from the equation is 17190.
Thus, the age of the fossil is mostly likely to be 17190 years old. 
8 0
3 years ago
Use your answers from questions 1 and 2 as the basis for the first section of your lab report. This section provides your reader
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8 0
3 years ago
1. The manufacturer of the vinegar used in the experiment stated that the vinegar contained 5.0% acetic acid. What is the percen
Naddik [55]

Answer:

72.8 % (But verify explanation).

Explanation:

Hello,

In this case, with the following obtained results, the percent error is computed as follows:

Volume of vinegar= 7.0 mL

Volume of NaOH= (7+6.6+6.4)/3= 6.7 mL

Used concentration of NaOH= 1.5M

Concentration of acetic acid= (concentration of NaOH*volume of NaOH)/volume of vinegar= (6.7mL*1.5M)/7.0M= 1.44M

Assuming we have 100 mL (0.100L) of vinegar, moles of acetic acid in vinegar = 1.44M x 0.100 L= 0.144 mol

Mass of acetic acid in 100g of vinegar = 0.144 mol x 60.0g/mol= 8.64 g

% of acetic acid in vinegar=8.64 %

% error in percentage of acetic acid = [(8.64% - 5.0%)/5.0] x 100=72.8 %

Clearly, this result depend on your own measurements, anyway, you can change any value wherever you need it.

Regards.

8 0
3 years ago
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