Wonderful! You gave us everything we could ever possibly want
to know, except the QUESTION. Fortunately, here at Brainly, we
have five Hogwarts drop-outs who work weekends for us as our
Department of Clairvoyance. When people post an intriguing
question but leave out some important part of it, our D of C can
usually fill in the missing part for us ... especially on weekends.
The question you left out is:
What is the next time that a red bus and a blue bus
will both leave the stadium together, simultaneously
and also both at the same time ?
Since red buses leave every 6 minutes starting at 4:00, and
blue buses leave every 8 minutes starting at 4:00, they both
leave simultaneously and also at the same time at minutes
after 4:00 that are common multiples of 6 and 8.
The least common multiple of 6 and 8 is 24 . After that,
every multiple of 24 is another common multiple of 6 and 8.
24 minutes is 4 red buses and 3 blue buses ... exactly !
A red bus and a blue bus will leave the stadium together at 4:24 .
After that, it will happen again at 24-minute intervals ... at 4:48,
5:12, 5:36, 6:00, . . . etc.
In this right triangle<span>, you are given the measurements for the hypotenuse, c, and one leg, b. The hypotenuse is always opposite the right angle and it is always the longest side of the </span>triangle<span>. To find the length of leg a, substitute the known values into the Pythagorean Theorem. </span>Solve<span> for a</span>2<span>.
take 26 and 22 add them together. then dived by 2</span>
0.067 is the answer for this
