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3 years ago

Let f(x) = 2x; its inverse is f1(x) = log2x. If f(5) = 32, what is f-1(32)?

Mathematics

1 answer:

PtichkaEL [24]3 years ago

3 0

Answer:

Step-by-step explanation:

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Peytons car used 6 gallons to travel 192 miles how many gallons of gas would she need t I travel 480 miles

ELEN [110]

Answer:

15 gallons

Step-by-step explanation:

if 6gallons = 192 miles

then x gallons 480 miles

x = (6*480)/192

x = 2880/192

x = 15 gallons

5 0

3 years ago

Please help me with these two questions

KonstantinChe [14]

Answer:

#1 is 60°, #2 is 55°

Step-by-step explanation:

all angles in a triangle add up to 180° so u can just subtract from that for the missing angles. :)

4 0

3 years ago

Show how u got the answer 309×42

luda_lava [24]

3
1
390
x 42
-------
1282
1564
----------------

the answer would be 16380
Hope this helped :)

4 0

3 years ago

Identify the square root of 2 as either rational or irrational, and approximate to the tenths place

Pie

Answer: Irrational

Step-by-step explanation:

It is irrational because you cannot multiply a number by the same number to get the square root of 2.

I think the approximation is 1.4 or 1.42

6 0

3 years ago

Find the 2nd Derivative:<br> f(x) = 3x⁴ + 2x² - 8x + 4

ad-work [718]

Answer:

$f''(x)=36x^2+4$

Step-by-step explanation:

Let's start by finding the first derivative of $f(x)= 3x^4+2x^2-8x+4$ . We can do so by using the power rule for derivatives.

The power rule states that:

$\frac{d}{dx} (x^n) = n \times x^n^-^1$

This means that if you are taking the derivative of a function with powers, you can bring the power down and multiply it with the coefficient, then reduce the power by 1.

Another rule that we need to note is that the derivative of a constant is 0.

Let's apply the power rule to the function f(x).

$\frac{d}{dx} (3x^4+2x^2-8x+4)$

Bring the exponent down and multiply it with the coefficient. Then, reduce the power by 1.

$\frac{d}{dx} (3x^4+2x^2-8x+4) = ((4)3x^4^-^1+(2)2x^2^-^1-(1)8x^1^-^1+(0)4)$

Simplify the equation.

$\frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x^1-8x^0+0)$
$\frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x-8(1)+0)$

$\frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x-8)$
$f'(x)=12x^3+4x-8$

Now, this is only the first derivative of the function f(x). Let's find the second derivative by applying the power rule once again, but this time to the first derivative, f'(x).

$\frac{d}{d} (f'x) = \frac{d}{dx} (12x^3+4x-8)$

$\frac{d}{dx} (12x^3+4x-8) = ((3)12x^3^-^1 + (1)4x^1^-^1 - (0)8)$

Simplify the equation.

$\frac{d}{dx} (12x^3+4x-8) = (36x^2 + 4x^0 - 0)$
$\frac{d}{dx} (12x^3+4x-8) = (36x^2 + 4(1) - 0)$
$\frac{d}{dx} (12x^3+4x-8) = (36x^2 + 4 )$

Therefore, this is the 2nd derivative of the function f(x).

We can say that: $f''(x)=36x^2+4$

6 0

2 years ago

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