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3 years ago

How can graphing be applied to solving systems of non-linear equations?

Mathematics

2 answers:

scZoUnD [109]3 years ago

6 0

Answer:

if we are given a system of non-linear equations than we can plot the graph of the system of equations in the coordinate plane and depending on the sign of the inequality shade the region. and see the intersection region to obtain the feasible region and also the intersection point of the two plane in order to obtain a optimal solution.

Constraints play a vital role in the real-world situation.

For example: we are given a cost of 1 pencil and one pen and we are given the maximum amount one has: then this problem could be modeled by the inequalities.

siniylev [52]3 years ago

5 0

The question is asking to states on how can graphing be applied to solving systems of non-linear equation, and base on my research, I would say that when you have non linear equation and plot them, you can obtains the points where those function intersect, so they are possible solution. Constraints could be use as guide line or model.

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Which inequality is equivalent to this one? Y-8≤-2

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Answer:

y-8+8

Step-by-step explanation:

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3 years ago

What is the slope of the line

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3/2

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2 years ago

Three times as many children as adults attended a concert on Saturday. An adult ticket cost $7 and a child’s ticket cost $3. The

Ierofanga [76]

For this case we propose a system of equations:

x: Let the variable representing the number of children in the concert

y: Let the variable representing the number of adults at the concert

According to the assistance we have:

$x = 3y$

According to the cost we have:

$3x + 7y = 6000$

Substituting the first in the second equation we have:

$3 (3y) + 7y = 6000\\9y + 7y = 6000\\16y = 6000\\y = \frac {6000} {16}\\y = 375$

Thus, the concert was 375 adults.

On the other hand we have:

$x = 3 (375) = 1125$

Thus, the concert was 1125 children.

In total they were:

$375 + 1125 = 1500$ people

ANswer:

The concert was 1500 people

3 0

3 years ago

How do you compute unit rates associates with ratios and fractions?

Crazy boy [7]

Compute unit rates associated with ratios of fractions, including ratios of lengths, areas and other quantities measured in like or different units. For example, if a person walks 1/2 mile in each 1/4 hour, compute the unit rate as the complex fraction 1/2/1/4 miles per hour, equivalently 2 miles per hour. ... hope this helps.

5 0

3 years ago

In the book,the distance between two planets is given as 4.07×10^¹² kilometres. The speed of light is 1.1×10^⁹ kilometres per ho

Sphinxa [80]

Answer:

3700hours

154days

Step-by-step explanation:

Speed can be defined as the distance cover per time, it can be expressed as

Speed= distance/ time........eqn(1)

Given:

distance between two planets= 4.07×10^¹²

speed of light = 1.1×10^⁹ kilometres per hour

Time= ??

Then substitute the values into equation (1) we have

Speed= distance/ time

1.1×10^⁹ kilometres per hour= 4.07×10^¹²kilometre/ time

Cross multiply, we have

Time= (4.07×10^¹²kilometre) /(1.1×10^⁹ kilometres per hour)

Time= 3700hours.

To convert to day, we know that

60 minute= 1hour

24hour=1day

Time= (3700hour×1day)/24hour

Time= 154days approximately.

Hence, the time taken for light to travel from one of these planets to the other is 154days or 3700hours

7 0

3 years ago