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aivan3 [116]
2 years ago
8

What ordered pair is a solution of the equation? y=-2x-5

Mathematics
2 answers:
Andru [333]2 years ago
5 0

2(0)  + y = 5

y = 5

  • The ordered pair is (0,5).
ioda2 years ago
3 0

\sf \underline{Answer:}

Pick any value for x, like x = 0, plug it into the equation, and get the value for y. For x = 0,

2(0) + y = 5

y = 5

The ordered pair is (0,5). Find other ordered pairs using the same reasoning.

You might be interested in
75 POINTS ASAP HELP
katrin2010 [14]

Answer:

It is called the constant ratio.

3 0
3 years ago
Read 2 more answers
Just 4 people who need helppp
Arturiano [62]

Answer:

1/2 ÷ 4 = 8

Step-by-step explanation:

Dividing fractions is as easy as pie. Flip the second and multiply.

1/2 ÷ 4 = 1/8

A whole number secretly has a 1 underneath, like this: 4/1

Flip the second number over to get 1/4, then multiply straight across.

\frac{1}{2} × \frac{1}{4} = \frac{1}{8}

Try to do the same for the other answers and see if they're right (they're not).

1/8 x 1/6 = 1/48

1/3 x 1/4 = 1/12

1/9 x 1/2 = 1/18

4 0
2 years ago
Read 2 more answers
Using the binomial theorem, expand the expression (4 + y) to the power of 4
Flauer [41]

Answer:

When raised to the power of 4, the binomial (4 + y) expands to:

y^4 + 16y^3 + 96y^2 + 256y + 256

Step-by-step explanation:

(4 + y)^4 \\= (y^2 + 8y + 16)^2\\= y^4 + 8y^3 + 16y^2 + 8y^3 + 64y^2 + 128y + 16y^2 + 128y + 256\\= y^4 + 16y^3 + 96y^2 + 256y + 256

8 0
3 years ago
Please explain this to me!
Charra [1.4K]
One meaning of a 'linear' equation is that if you draw the graph
of the equation, the graph will be a straight line.

That's an easy way to test the equation . . . find 3 points on the
graph, and see whether they're all in a straight line.

This equation is        y  =  4 / x .

To find a point on the graph, just pick any number for 'x',
and figure out the value of 'y' that goes with it.
Do that 3 times, and you've got 3 points on the graph.

Here ... I'll do 3 quick points:

Point-A:  x = 1     y =  4 / 1    =  4
Point-B:  x = 2     y =  4 / 2    =  2
Point-C:  x = 4     y =  4 / 4    =  1

Look at this:

Slope of the line from point-A to point-B
                         = (change in 'y') / (change in 'x') =  -2 .

Slope of the line from point-B to point-C
                         = (change in 'y') / (change in 'x') =  -1/2 .

The two pieces of line from A-B and from B-C don't even have
the same slope, so they're not pieces of the same straight line !
So my points A, B, and C are NOT in a straight line.

So the equation is NOT linear.

Try it again with three points of your own.
5 0
3 years ago
Me pueden ayudar en esta ecuación bicuadratica, porfaaa: 9p⁴=—12x²—6/9
Dominik [7]

Answer:

x = -1.129i, -0.241i, 0.241i o 1.129i.

Tenga en cuenta que i = √(-1), i es el representante de un número complejo.

x = -1.129i, -0.241i, 0.241i or 1.129i.

Note that i = √(-1), i is the representative of a complex number.

Step-by-step explanation:

Pregunta correcta

¿Me pueden ayudar en esta ecuación biquadratica, por favor: 9x⁴ = —12x² - 6/9

Solución

9x⁴ = —12x² - 6/9

9x⁴ + 12x² + 6/9 = 0

multiplicar por 9

81x⁴ + 108x² + 6 = 0

Deje x² = y, entonces x⁴ = y²

81y² + 108y + 6 = 0

Resolviendo esta ecuación cuadrática

y = -0.0581 o y = -1.275

Recordemos, x² = y

x = ±√y

Si y = -0.0581

x = ± √(-0.0581) = ± 0.241i = 0.241i o -0.241i

Si y = -1.275

x = ± √(-1.275) = ± 1.129i = 1.129i o -1.129i

x = -1.129i, -0.241i, 0.241i o 1.129i.

Tenga en cuenta que i = √(-1), i es el representante de un número complejo.

¡¡¡Espero que esto ayude!!!

Correct Question

Can you help me in this biquadratic equation, please: 9x⁴ = —12x² — 6/9

Solution

9x⁴ = —12x² — 6/9

9x⁴ + 12x² + 6/9 = 0

multiply through by 9

81x⁴ + 108x² + 6 = 0

Let x² = y, then x⁴ = y²

81y² + 108y + 6 = 0

Solving this quadratic equation

y = -0.0581 or y = -1.275

Recall, x² = y

x = ±√y

If y = 0.0581

x = ±√(-0.0581) = ±0.241

If y = -1.275

x = ± √(-1.275) = ± 1.129i = 1.129i or -1.129i

Hence x = -1.129i, -0.241i, 0.241i or 1.129i.

Note that i = √(-1), i is the representative of a complex number.

Hope this Helps!!

5 0
3 years ago
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