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4 years ago

Can someone please help me

Mathematics

1 answer:

uranmaximum [27]4 years ago

7 0

If we have y = f(x), then vertically stretching that by a factor of k gives y = k*f(x) as the new function. This means we simply stick a 3 in front of the 2^x to get our answer.

Answer: Choice C) g(x) = 3*2^x

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1. $17.04 for 4 packages

yan [13]

answer

they are each $4.26

5 0

4 years ago

Identify all the lines of symmetry of the following rectangle.

ladessa [460]

The triangle presented in the image has 2 axes of symmetry because it is only possible to divide it 2 times.

<h3>What are axes of symmetry?</h3>

The axes of symmetry are a concept of geometry that are classified into two groups:

The plane axis of symmetry: This is an imaginary line that divides a figure into two parts, ensuring that the symmetrical points are at the same distance from it.
The axis of axial symmetry: This is the symmetry around an axis, it is a point of translation and rotation in which all the semi-planes taken from a certain perpendicular bisector have identical characteristics.

According to the above, it can be inferred that the rectangle presented in the image has only two axes of symmetry.

Learn more about symmetry in: brainly.com/question/17759737

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4 0

3 years ago

A bookstore had 60 copies of a magazine. Yesterday, it sold 2/3 of them. Today, it sold 4/5 of what remained. How many copies do

laiz [17]

Answer:

4 copies

Step-by-step explanation:

After yesterday's sales, 1/3 of the original supply remained. After today's sales, 1/5 of that value remain. So the remaining number is ...

60·(1/3)(1/5) = 60/15 = 4

4 0

3 years ago

Mr. Salazar assigns the same number of homework questions each school day. The ratio table below shows the total number of homew

GalinKa [24]

Answer: 80

Step-by-step explanation:

Looking at the ratios in the table, the number of days to number of questions is 1:5 (4x5=20; 8x5=40;11x5=55). So for 16 days it will be 16x5=80

6 0

3 years ago

Read 2 more answers

Eliminate the parameter and obtain the standard form of the rectangular equation. Ellipse: x = h + a cos(θ), y = k + b sin(θ) Us

gayaneshka [121]

Answer:

a) $(\frac{x-h}{a})^2+ (\frac{y-k}{b})^2=1$

b) $x=1+5 \,cos(\theta)\,,\,y=4\,sin(\theta)$

c) $\frac{(x-1)^2}{25}+ \frac{y^2}{16}=1$

Step-by-step explanation:

Start by isolating the trigonometric expression in both equations, ad then use the Pythagorean identity:

$cos^2(\theta)+sin^2(\theta)=1$

to obtain the standard equation of a conic.

$x=h+a\,cos(\theta)\\x-h=a\,cos(\theta)\\cos(\theta)=\frac{x-h}{a}$ $y=k+b\,sin(\theta)\\y-k=b\,sin(\theta)\\sin(\theta)=\frac{y-k}{b}$

then:

$cos^2(\theta)+sin^2(\theta)=1\\(\frac{x-h}{a})^2+ (\frac{y-k}{b})^2=1$

this is the equation of an ellipse centered at (h,k), and with horizontal axis length = 2a , and vertical axis length = 2b.

The parametric equations are those we started with:

$x=h+a \,cos(\theta)\,,\,y=k+b\,sin(\theta)$ but we need to find the appropriate parameters for the requested ellipse, as shown below.

For an ellipse of vertices (-4,0) a,d (6,0) and foci at (-2,0) and (4.0), we are dealing with an ellipse with major horizontal axis on the line y=0, and major diameter length of 10 units, so the parameter $a=5$ . The center of the ellipse is therefore at (1,0).

We recall that the vertices of a translated horizontal ellipse are located at $(a+h,k)$ and $(-a+h,k)$ , then k=0 to satisfy the information given (-4,0) & (6,0), and since $a=5$ , we deduce that $a+h = 6$ and therefore h=1.

To find "b" (the only parameter missing for the standard equation of the conic), we need the information on the foci (-2,0) and (4,0) which must equal (h-c,k) and (h+c,k) with k=0 and h=1 which then gives that c=3

Now using the formula for the parameter "c" of the foci: $c=\sqrt{a^2-b^2}$

$c=\sqrt{a^2-b^2}\\3=\sqrt{5^2-b^2}\\9=25-b^2\\b^2=25-9\\b^2=16\\b=4$

Then we can write the equation of this ellipse in standard form as:

$(\frac{x-h}{a})^2+ (\frac{y-k}{b})^2=1\\(\frac{x-1}{5})^2+ (\frac{y-0}{4})^2=1\\\\(\frac{x-1}{5})^2+ (\frac{y}{4})^2=1\\\frac{(x-1)^2}{25}+ \frac{y^2}{16}=1$

8 0

3 years ago