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Rashid [163]
3 years ago
12

1. $17.04 for 4 packages

Mathematics
1 answer:
yan [13]3 years ago
5 0

answer

they are each $4.26

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Can I get step by step help on numbers 52,54,60, and 64 please
Korolek [52]

Answer:

52: 8-Z

54: 18+X

60: 12.3

64: 2.5

52: 8 subtracted from z, the equation will only be 8-z because we do not know what z is.

54: 18 more than a number, we do not know what the number is so we will name it X, more than is adding, so the equation will look like this, 18+X

60: Since y is 6.7, all you have to do is subtract 19-6.7.

64: Since n is 7.5 just divide 7.5 from 3 and you will get 2.5.

7 0
3 years ago
{x | x &lt; 2}<br><br> how do I solve this
vaieri [72.5K]

Answer:

The set of all numbers less than 2.

Step-by-step explanation:

{x | x < 2}

-Means  all values of x that are less than 2.

- this is the set of all numbers less than 2

4 0
3 years ago
Solve for x ... please help
Mrac [35]

Answer:

7x + 49 \degree = 2x + 94\degree \\ 7x - 2x = 94\degree - 49 \degree \\ 5x = 45\degree \\ x =  \frac{45}{5}  \\ x = 9 \\ check \\ 7(9) + 49 = 112\degree \\ 2(9) + 94 = 112\degree

5 0
2 years ago
Scsb17 what is -5 + 8x - 10
bogdanovich [222]
The answer is 5+8x i think
4 0
3 years ago
Read 2 more answers
Click here please. The problems are in picture format
padilas [110]

First picture:

You got the first two right (good job!), so I'll just tackle the third one. If you have to compute f(x-4), it means that you have to substitute x-4 in place of x. Differently from the first two points, this will generate a new function, rather than a specific value:

f(x) = \sqrt{x+4}+2 \implies f(x-4) = \sqrt{(x-4)+4}+2 = \sqrt{x}+2

Second picture:

Given the point (x,y) highlighted in the picture, you can deduce that the base is 2x units long (since it spans from (-x,0) to (x,0)) and the height is y units long (because it spans from (x,0) to (x,y)). So, the area of the rectangle is the multiplication between base and height:

A = 2xy

But we know that y=f(x)=\sqrt{36-x^2}, so we have

A = 2x\sqrt{36-x^2}

The domain of this function is given by the domain of the square root: we want its argument to be non, negative, so we have

36-x^2 \geq 0 \iff x^2 \leq 36 \iff -6 \leq x \leq 6

But since the problem is symmetric, the answer is

0 \leq x \leq 6

You can only see the answer 0 < x < 6 because, if you choose x=0 or x=6, the rectangle degenerates to a segment, and your exercise doesn't like this scenario, apparently

4 0
3 years ago
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