Answer:
Julian has <em>16 dimes</em> and <em>6 quarters</em>
Step-by-step explanation:
Let's suppose Julian has q quarters and d dimes
The total coins are 22, that is
q+d=22
q=22-d [1]
The total amount of money he has is 310 cents which are made of 10d dimes and 25q quarters
10d+25q=310
Simplifying by 5
2d+5q=62
Using the relation [1]
2d+5(22-d)=62
2d+110-5d=62
3d=48 => d=16
q=22-16 = 6
So Julian has 16 dimes and 6 quarters
Answer:
m = - 3
Step-by-step explanation:
a³ + 27 ← is a sum of cubes and factors in general as
a³ + b³ = (a + b)(a² - ab + b²), thus
a³ + 27
= a³ + 3³
= (a + 3)(a² - 3a + 9)
comparing a² - 3a + 9 to a² + ma + 9, then
m = - 3
Answer:
$55.55
Step-by-step explanation:
To find the cost of the purchase add 4 times the cost of one large sack to the cost of one small sack:
4($11.55) +($9.35) = $46.20 + 9.35 = $55.55
The cost of 4 large sacks and 1 small sack would be $55.55.
686 barrels left. If I'm not mistaken this should just be simple subtraction
Answer:
-1/2
Step-by-step explanation:
