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3 years ago

How does an impulse propagate down the axon

1 answer:

5 0

When action potentials reach the end of the axon, they stimulate opening of Ca2+ channels, causing a release of neurotransmitters to the post-synaptic cell. How does and impulse propagate down the axon? The stimulus causes a start of the action potential and it moves down the axon without the ions moving down

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Frequency and pitch are (blank) proportional. Therefore, as frequency increases, the perceived pitch (blank) by the same factor.

Alborosie

Answer:

1. Directly

2. Increases

3. Frequency

4. Pitch

8 0

3 years ago

Read 2 more answers

A ray of light (f = 5.09 x 1014 Hz) is incident on the boundary between air and an unknown material X at an angle of incidence o

11Alexandr11 [23.1K]

Answer:

A) Material X is flint glass

B) Speed of light in the X material is 1.807 x $10^{8}$ m/s

C) Angle of refraction of light in medium X is $29.57^{o}$

Explanation:

Given data:

frequency of the light f = 5.09 x $10^{14}$ Hz

angle of incidence Θ $_{i}$ = $55^{o}$

index of refraction of material $n_{2}$ = 1.66

A) To find material X

Given the index of refraction is 1.66 and hence the material is the flint glass

B) To calculate the speed of light in the material.

We know that the relation between index of refraction (n), velocity of light (c = 3 x $10^{8}$ m/s) and velocity of light is given by the equation:

n = c/v

Hence,

Speed of light in the X material v = c/n

= $\frac{3 x 10^{8} }{1.66}$

= 1.807 x $10^{8}$ m/s

C) To calculate angle of refraction of light in medium X

We know that the Snell's law states that

$n_{1} sin$ Θ $_{i}$ = $n_{2} sin$ Θ $_{r}$

$n_{1}$ = incident index

$n_{2}$ = refracted index

Θ $_{i}$ = incident angle

Θ $_{r}$ = refracted angle

In given problem, $n_{1}$ = 1 since medium is air

Substituting the known values, we get

1 x $sin$ $55^{o}$ = 1.66 x $sin$ Θ $_{r}$

$sin$ Θ $_{r}$ = $sin$ $55^{o}$ /1.66

= 0.4935

Hence, angle of refraction of light in medium X Θ $_{r}$ = $sin^{-1}$ (0.4935)

= $29.57^{o}$

4 0

3 years ago

What relationship exists betwen air resistance and acceleration of falling objects

ololo11 [35]

They both make a thing go faster and slower but the relationship is force.

5 0

4 years ago

Read 2 more answers

A plastic beach ball has radius 21.6 cm and mass 0.100 kg, not including the air inside. Assume the air density is 1.30 kg/m3 bo

vichka [17]

Answer: 0.1416 kg

Explanation:

Total Mass = Mass of beach ball + Mass of air inside

Mass of beach ball = 0.100 kg

Mass of air = density * volume

Density = 1.30 kg/m^3

Radius (r) = 21.6 cm = 0.216 m

Volume (sphere) = π * r^3 = π * (0.216)^3 = 0.032 m^3

Hence:

Mass of air = 1.30 * 0.032 = 0.0416 kg

Total Mass = 0.100 + 0.0416 = 0.1416 kg

3 0

3 years ago

A plumber uses a spanner on a tap. She puts a force of 200N on the spanner 30cm from the tap. What is the size of the moment?

zaharov [31]

Answer:

60Nm

Explanation:

Given data

Applied force= 200N

length of spanner= 30cm to meter

= 30/100= 0.3m

We know that the formula for the moment is

P=Fl

that is

P= force * length

P= 200*0.3

P= 60Nm

Hence the moment is 60Nm

7 0

3 years ago