here we have to calculate the net positive charge present on he surface of the conducting sphere.
as the sphere is a conducting one the,the charge will be stored on its surface.
though the charge is present at the surface,still it will behave just like the total charge is concentrated at the centre of the sphere.
the electric field at outside of the sphere is E=
as E= 
so V=
here V=27 volt,radius of sphere is 0.800 m and the point at which the potential is considered is at 1.20 m from th centre of the sphere.hence the point is at the outside of the sphere .
hence we have 27=
q=27×
coulomb
=3.6×
coulomb [ans]
Explanation:
You are given the initial velocity, the displacement, and the acceleration. You're looking for the final velocity. So you use the equation:
v² = v₀² + 2aΔy
When you solve for v, you take the square root. Your calculator will return a positive answer, but there are actually two possible answers: positive and negative.
v = ±√(v₀² + 2aΔy)
You must use the physical context of the problem. If we take up to be the positive direction, then v must be negative, since the projectile is moving down.
When a battery is connected to a circuit, the electrons from the anode travel through the circuit toward the cathode in a direct circuit. The voltage of a battery is synonymous with its electromotive force, or emf. This force is responsible for the flow of charge through the circuit, known as the electric current.
Answer:
Clyde will provide greater impulse
Explanation:
We have given that Al exerts a force of 200 N for 5 sec
We know that impulse is given by, impulse = force ×time = 200×5 =1000 N-s
Bill exerts a force of 500 N for 2 sec
So impulse = 500×2 = 1000 N-s
Now the force exerted by Clyde 300 N for 4 sec
So impulse = 300×4 = 1200 N-s
From above calculation we can see that Clyde provide greater impulse than any other
