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4 years ago

What relationship exists betwen air resistance and acceleration of falling objects

Physics

2 answers:

ololo11 [35]4 years ago

5 0

They both make a thing go faster and slower but the relationship is force.

Katen [24]4 years ago

4 0

They are both forces that exist when an object is falling. Terminal velocity occurs when gravitational acceleration is equivalent to air resistance. :)

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A 50.0 kg object is moving at 18.2 m/s when a 200 N force

gayaneshka [121]

Answer:

distance = 21.56 m

Explanation:

given data

mass = 50 kg

initial velocity = 18.2 m/s

force = -200 N ( here force applied to opposite direction )

final velocity = 12.6 m/s

solution

we know here acceleration will be as

acceleration a = force ÷ mass

a = $\frac{-200}{50}$ = -4 m/s²

we get here now required time that is

required time = $\frac{V_{(final)} - V_{(initial)}}{a}$ ...............1

put here value

required time = $\frac{12.6-18.2}{-4}$

so distance will be

distance = $\frac{V_{(final)}^2 - V_{(initial)}^2}{2a}$ ........2

distance = $\frac{12.6}^2 -{18.2}^2}{2\times (-4)}$

distance = 21.56 m

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3 years ago

At a sudden contraction in a pipe the diameter changes fromD1toD2. The pressure drop,Δp, which develops across the contraction i

Sever21 [200]

Answer: The working and answer can be viewed from the screenshots below. Thanks

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4 years ago

How would local winds be affected if water and land release heat at the same time

BlackZzzverrR [31]

Local winds are driven by temperature differences in areas fairly close to each other. If water and land absorbed and released heat at the same rate, there wouldn't be any temperature differences and nothing to power local winds. See the related link for further information.

8 0

3 years ago

A heavy object and a light object are dropped from the same height. If we neglect air resistance, which will hit the ground firs

Maksim231197 [3]

Answer:

None, both objects will hit ground at the same time.

Explanation:

Assuming no air resistance present, and that both objects start from rest, we can apply the following kinematic equation for the vertical displacement:

$\Delta h = \frac{1}{2}*g*t^{2} (1)$

As the left side in (1) is the same for both objects, the right side will be the same also.
Since g is constant close to the surface of the Earth, it's also the same for both objects.
So, the time t must be the same for both objects also.

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lord [1]

just listen I am also confused in this question if you get the answer so please just tell me also

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4 years ago