The function f(x) = 6^(x)-2 has an x-intercept at approximately <span>(0.39, 0)
f(x) = 0 = 6^(x) - 2
2 = 6^(x)
log(2)/log(6)= x
x = 0.3868 = 0.39</span>
The answer to this question is A) (0.39, 0).
Hey There!
One of the numbers she might be thinking of could be 1,298, because it rounds to 1,300 in the nearest hundreds, and for the nearest tens. Remember, when a number is greater than 5 you round it to the nearest ten. Same rule applies for the hundreds, but the number has to be in the tens place instead of the ones place.
Have A Brainly Day :)
Send me a message for more help :)
2(32-3)^3
= 2(29) ^3
=78 ^ 3
= 78 times 78 times 78
= 42,588
Answer:
0.625N
Step-by-step explanation:
0.50N
0.80M = 0.50N, so M = ------------
0.80
and so:
0.50N
N*M = N*------------ = (5/8)N, or 0.625N
0.80
Answer:
$10,144.93
Step-by-step explanation:
Amount formula; A = (Principal* rate* time) +Principal
A= (P*r*t) +P
A= 14,000
r= 9.5% OR 0.095 as a decimal
t= 4
Plug the numbers into the formula;
14,000 = (P* 0.095 *4 ) +P
14,000 = 0.38P +P
14,000 = 1.38P
Divide both sides by 1.38 to solve for P;
14,000/1.38 = P
P= 10,144.9275
Therefore, the present value (Principal) = $10,144.93
