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goblinko [34]
3 years ago
7

Bütünler iki açıdan büyük olanın ölçüsü küçük olanın ölçüsünün 4 katından 10°eksiktir. Buna göre büyük açı kaç derecedir?​

Mathematics
1 answer:
Solnce55 [7]3 years ago
3 0

Answer:

Step-by-step explanation:

x+y = 360

y = 360-x

x = 4y-10

x = 4(360-x)-10

x = 1440-4x-10

5x = 1430

x = 286°

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Is-6 is greater then -4.50
alexgriva [62]

-4.50 is closer to 0 so no

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3 years ago
How do I solve this question?
asambeis [7]
This is a perfect square trnomial
(a+b)²=a²+2ab+b²
we see that a=5x and b=2

(5x)²+2(5x)(2)+2²=0
factor
(5x+2)²=0
set equal to zero
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5 0
3 years ago
In a random sample of 80 teenagers, the average number of texts handled in a day is 50. The 96% confidence interval for the mean
Nastasia [14]

Answer:

a) \bar X =\frac{46+54}{2}=50

And the margin of error is given by:

ME= \frac{54-46}{2}= 4

The confidence level is 0.96 and the significance level is \alpha=1-0.96=0.04 and the value of \alpha/2 =0.02 and the margin of error is given by:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

We can calculate the critical value and we got:

z_{\alpha/2} = 2.05

And if we solve for the deviation like this:

\sigma = ME * \frac{\sqrt{n}}{z_{\alpha/2}}

And replacing we got:

\sigma =4 *\frac{\sqrt{80}}{2.05} =17.45

b) ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}=2.05 *\frac{17.45}{\sqrt{160}}=2.828

And as we can see that the margin of error would be lower than the original value of 4, the margin of error would be reduced by a factor \sqrt{2}

Step-by-step explanation:

Previous concepts  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X represent the sample mean  

\mu population mean (variable of interest)  

\sigma represent the population standard deviation  

n=80 represent the sample size  

Solution to the problem

Part a

The confidence interval for the mean is given by the following formula:  

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)  

For this case we can calculate the mean like this:

\bar X =\frac{46+54}{2}=50

And the margin of error is given by:

ME= \frac{54-46}{2}= 4

The confidence level is 0.96 and the significance level is \alpha=1-0.96=0.04 and the value of \alpha/2 =0.02 and the margin of error is given by:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

We can calculate the critical value and we got:

z_{\alpha/2} = 2.05

And if we solve for the deviation like this:

\sigma = ME * \frac{\sqrt{n}}{z_{\alpha/2}}

And replacing we got:

\sigma =4 *\frac{\sqrt{80}}{2.05} =17.45

Part b

For this case is the sample size is doubled the margin of error would be:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}=2.05 *\frac{17.45}{\sqrt{160}}=2.828

And as we can see that the margin of error would be lower than the original value of 4, the margin of error would be reduced by a factor \sqrt{2}

5 0
3 years ago
Are these triangles congruent ?
Vadim26 [7]

Answer:no

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Four different roads from Town A to Town B, and three different roads run from Town B to Town C. Two roads also run from Town A
LekaFEV [45]

Answer:

196

Step-by-step explanation:

To solve this, I broke it down into two parts.

A. Number of routes going to Town C

4 x 3 + 2 = 14

B. Number of routes going back to Town A

3 x 4 + 2 = 14

From here, it is easy to see what to do. Since there are 14 routes going to Town C and 14 routes going back, the answer is 14 x 14 = 196.

5 0
3 years ago
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