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telo118 [61]
3 years ago
9

What is 0.4698 repeating decimal as fraction

Mathematics
1 answer:
Papessa [141]3 years ago
4 0
The answer is 522 over 1111
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Plxxx help me giving brainlyest to the first and correct answer :)
Jobisdone [24]

Answer:

A.29820

Step-by-step explanation:

39,594 - 9,774

29820

8 0
1 year ago
Read 2 more answers
Write 615000 in scientific notation​
lianna [129]

Answer:

6.15 × 10⁵

Step-by-step explanation:

When converting a number of scientific notation, we need to move the decimal point until the number is greater than 1 and less than 10, then multiply this by 10 to the power of the number of places we moved the decimal point (negative when moving it forwards, positive when moving it backwards).

Therefore, 615000 = 6.15 × 10⁵

4 0
2 years ago
The length of a park is 2/5 miles and the area is 9/10 square miles. What is the width of the park?
OverLord2011 [107]

To find the width, divide the area by the length.

Width = 9/10 / 2/5

When dividing fractions flip the second one over and multiply:

Width = 9/10 x 5/2 = (9 x5) / (10 x 2) = 45/20 = 2 and 1/4 miles.

3 0
2 years ago
Write the point slope form of the equation of the line that passes through the points (-3,2) and (-5,3).
DaniilM [7]

Answer:

The answer would be B i think .

7 0
2 years ago
15 point question
Natalka [10]

Answer:

It will cost $12.5 per person to charter a bus for 36 passengers

Step-by-step explanation:

The cost per person c of chartering a tour bus  varies inversely as the number of passengers  n.

We can write:

c\:\alpha \:\frac{1}{n} \\c=\frac{k}{n}

where k is constant of proportionality

We are given when c = 22.50, n = 20

We need to find c when n = 36

First using c = 22.50, n = 20 we will find k, the constant of proportionality

c=\frac{k}{n}\\22.50=\frac{k}{20}\\k=22.50 \times 20\\k=450

So, we get k = 450

Now, we will find c when n = 36

c=\frac{k}{n}\\c=\frac{450}{36}\\c=12.5

So, we get the value of c: c = 12.5

Therefore, It will cost $12.5 per person to charter a bus for 36 passengers

8 0
3 years ago
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