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pav-90 [236]
3 years ago
11

Which graph shows the solution to the system of equations? Solve the system graphically. Click on the graph until the correct so

lution appears.
2x + 3y = 6
x + y = 4

Mathematics
2 answers:
8_murik_8 [283]3 years ago
7 0

Answer with Step-by-step explanation:

As we can see from the graph solutions are:

Graph 1: (-2,6)

it doesn't satisfy the equation 2x + 3y = 6

Graph 2: (5,-1)

it doesn't satisfy the equation 2x + 3y = 6

Graph 3: (2,2)

it doesn't satisfy the equation 2x + 3y = 6

Graph 4: (6,-2)

It satisfies both the solutions

Hence, solution of the system

2x + 3y = 6

x + y = 4 is:

(6,-2)

Given by the fourth graph

romanna [79]3 years ago
6 0
The correct answer is:  "Graph [D]:  "the fourth graph provided".
__________________________________________________
Explanation:  By looking at each graph in each of the 4 (FOUR) answer choices provided;   "Graph [D]" (the fourth answer choice) is the only graph in which two (2) of the same lines intersect at the same point with the particular coordinates: 
  "(6, -2)" ;  that are correct for BOTH of the 2 equations given.
Furthermore, we see that the coordinates for BOTH of the x and y- intercepts for BOTH of the equations given in this problem—are, in fact, points along EACH of the given corresponding 2 (two) corresponding lines in:  "Graph [D]".
_______________________________________________
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5 0
3 years ago
Suppose the following set of random numbers is being used to simulate the
Jobisdone [24]

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4 0
3 years ago
Read 2 more answers
1/2 ln(x + 3) - lnx = 0 solve for x
rusak2 [61]
1

 

Simplify \frac{1}{2}\imath n(x+3)​2​​1​​ın(x+3) to \frac{\imath n(x+3)}{2}​2​​ın(x+3)​​

\frac{\imath n(x+3)}{2}-\imath nx=0​2​​ın(x+3)​​−ınx=0


2

 

Add \imath nxınx to both sides

\frac{\imath n(x+3)}{2}=\imath nx​2​​ın(x+3)​​=ınx


3

 

Multiply both sides by 22

\imath n(x+3)=\imath nx\times 2ın(x+3)=ınx×2


4

 

Regroup terms

\imath n(x+3)=nx\times 2\imathın(x+3)=nx×2ı


5

 

Cancel \imathı on both sides

n(x+3)=nx\times 2n(x+3)=nx×2


6

 

Divide both sides by nn

x+3=\frac{nx\times 2}{n}x+3=​n​​nx×2​​


7

 

Subtract 33 from both sides

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6 0
4 years ago
Fruit:sugar in a ratio 2:3 if 8kg of fruit is used, how much sugar?
Vilka [71]
Hey there.

Considering our ratio from fruit to sugar is 2:3, this means we need to make a proportion. I will set this up below;

2:3 = 8:x; x is a variable substitute for our missing sugar value. Let's try to see if 2 divides into 8.
8 / 2 = 4; this means our scale factor of our ratio is 4x larger than the current value, so multiply 2 and 3 by 4 to solve for sugar.

2:3;

2 x 4 = 8; 8:x
3 x 4 = 12; 8:12.

12kg is the missing sugar value in our proportion; therefore, 12kg of sugar is used when 8kg of fruit is used.

I hope this helps!
6 0
4 years ago
A research group recruits 10 volunteers to try a new brand of tennis shoes. Only 5 volunteers will be selected to participate in
Neporo4naja [7]

Answer:

There are 253 ways to select 5 participants

Step-by-step explanation:

Total number of volunteers to try a new brand of tennis shoes = 10

Number of volunteers to be selected = 5

We are supposed to find number of ways the research group select 5 participants.

We will use combination:

Formula:^nC_r=\frac{n!}{r!(n-r)!}

Substitute n = 10 and r = 5

So,^{10}C_5=\frac{10!}{5!(10-5)!}

^{10}C_5=252

Hence There are 253 ways to select 5 participants

7 0
4 years ago
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