Y^4-4y^3+7y^2-6y-2y^3+8y^2-14y+12=
y^4-6y^3+15y^2-20y+12
or
y^3-4y^2+7y-6=y^3-4y^2+4y+3y-6=
y(y^2-4y+4)+3(y-2)=
y(y-2)^2+3(y-2)=(y-2)[y(y-2)+3]=(y-2)(y^2-2y+3)
(y^3-4y^2+7y-6)(y-2)=(y-2)^2(y^2-2y+3)
Answer: missing value is 3
Step-by-step explanation:To find the vertex form of parabola given in almost standard form were written following steps:
1. Write the function in standard form:
2. Factor a out of the first two terms:
3. Form a perfect square trinomial:
4. Write the trinomial as a binomial squared:
The vertex is (-3,-27).
Answer:
26 because if x= -7 then -3 X - 7 = +21
+21 +5 = 26
Answer:
Step-by-step explanation:
Figure it out yourself
