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Genrish500 [490]
3 years ago
10

Hello could anyone tell me what 12 plus 14 times 2000 divided by 13 is?

Mathematics
1 answer:
sveticcg [70]3 years ago
5 0
The exact answer is 2,165.846153846154
Hope this helpssss :)
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Which of the following is a solution to this inequality? y>1/2x+2
Travka [436]

I need help with this asw

5 0
3 years ago
Evaluate the expression \dfrac{7^2}{x^2-2} x 2 −2 7 2 ​ start fraction, 7, squared, divided by, x, squared, minus, 2, end fracti
sertanlavr [38]

Answer:

7

Step-by-step explanation:

We want to evaluate the fraction below for x = 3. We will put the value of x to be 3:

\dfrac{7^2}{x^2-2}\\\\= \dfrac{7^2}{3^2-2}\\\\= \dfrac{49}{9-2}\\\\= \dfrac{49}{7} = 7

The answer is 7.

3 0
3 years ago
In a statistics class there are 18 juniors and 10 seniors; 6 of the seniors are females and 12 of the juniors are males. If a st
Natasha_Volkova [10]

Answer:

P(a junior or a senior)=1

Step-by-step explanation:

The formula of the probability is given by:

P(A)=\frac{n(A)}{N}

Where P(A) is the probability of occurring an event A, n(A) is the number of favorable outcomes and N is the total number of outcomes.

In this case, N is the total number of the students of statistics class.

N=18+10=28

The probability of the union of two mutually exclusive events is given by:

P(AUB)=P(A)+P(B)

Therefore:

P(a junior or a senior) =P(a junior)+P(a senior)

Because a student is a junior or a senior, not both.

n(a junior)=18

n(a senior)=10

P(a junior)=18/28

P(a senior) = 10/28

P(a junior or a senior) = 18/28 + 10/28

Solving the sum of the fractions:

P(a junior or a senior) = 28/28 = 1

4 0
3 years ago
What are the coordinates of the point (10, -4) if it is reflected across the y- axis?
iVinArrow [24]

Answer:

(-10,-4)

Step-by-step explanation:

The point is moved to the other side of the y axis.

The y coordinate would stay the same and the x coordinate would move the same number of units but on the opposite side (that's why its -10).

4 0
3 years ago
why does the method for finding the volume of an irregular-shaped object work for regular-shaped objects as well?
kumpel [21]

Answer:

Its the same formula that your using to find a regular object as an irregular one. The only difference is that your adding the formula of multiple shapes together since an irregular shape consists of multiple regular ones

hope this helps!

5 0
3 years ago
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