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fgiga [73]
3 years ago
8

A room measures 12 feet by 15 feet. How many square feet of vinyl floor covering will it take to cover the floor

Mathematics
2 answers:
Elis [28]3 years ago
6 0

the question is asking for the Area of the floor

A = 12 * 15

A = 180 feet²

Finger [1]3 years ago
4 0

it would take 180 square feet (to find area do width by length)

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Brain boggling boggle help pls<br>:)<br>​
MArishka [77]
Just write some random reason for your random answer and that should do it
8 0
2 years ago
Find the values of​ x, y, and z in the triangle to the right. A triangle has angles labeled as follows: lower left, x degrees; t
Studentka2010 [4]

Given:

Consider the below figure attached with this question.

Angles of a triangle are x, y and z.

To find:

The values of x, y and z.

Solution:

If two angles are linear pair, then their sum is 180 degrees.

y+(3x+5)=180

y=180-3x-5

y=175-3x

Similarly,

z+(3x-5)=180

z=180-3x+5

z=185-3x

According the the angle sum property, the sum of all angles of a triangle is 180 degrees.

x+y+z=180

x+(175-3x)+(185-3x)=180

-5x+360=180

-5x=180-360

-5x=-180

Divide both sides by -5.

x=36

The value of x is 36.

y=175-3(36)

y=175-(108)

y=67

Now,

z=185-3(36)

z=185-108

z=77

Therefore, the values of x, y and z are 36, 67 and 77 respectively.

6 0
4 years ago
A Government company claims that an average light bulb lasts 270 days. A researcher randomly selects 18 bulbs for testing. The s
Fofino [41]

Answer:

31.92% probability that 18 randomly selected bulbs would have an average life of no more than 260 days

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

In this question, we have that:

\mu = 270, \sigma = 90, n = 18, s = \frac{90}{\sqrt{18}} = 21.2

What is the probability that 18 randomly selected bulbs would have an average life of no more than 260 days?

This is the pvalue of Z when X = 260. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{260 - 270}{21.2}

Z = -0.47

Z = -0.47 has a pvalue of 0.3192.

31.92% probability that 18 randomly selected bulbs would have an average life of no more than 260 days

5 0
3 years ago
K/2 - 1 = 1 solve for k
Nana76 [90]
K=4 would be the answer you’re looking for
6 0
3 years ago
McAllister et al. (2012) compared varsity football and hockey players with varsity athletes from noncontact sports to determine
jonny [76]

Answer:

t _{critical} = 1.760

t = 2.2450

d. 0.264

Step-by-step explanation:

The null hypothesis is:

H_o: \mu_1 - \mu_2 = 0

Alternative hypothesis;

H_a : \mu_1 - \mu_2 > 0\\

The pooled variance t-Test would have been determined if the population variance are the same.

S_p^2 = \dfrac{(n_1-1)S_1^2+(n_2-1)S^2_2}{(n_1-1)+(n_2-1)}

S_p^2 = \dfrac{(8-1)2.507^2+(8-1)2.8282^2}{(8-1)+(8-1)}

S_p^2 = 7.14

The t-test statistics can be computed as:

t= \dfrac{(x_1-x_2)-(\mu_1 - \mu_2)}{\sqrt{Sp^2 ( \dfrac{1}{n} +\dfrac{1}{n_2})}}

t= \dfrac{(9-6)-0}{\sqrt{7.14 ( \dfrac{1}{8} +\dfrac{1}{8})}}

t= \dfrac{3}{1.336}

t = 2.2450

Degree of freedom df = (n_1 -1) + ( n_2 +1 )

df = (8-1)+(8-1)

df = 7 + 7

df = 14

At df = 14 and ∝ = 0.05;

t _{critical} = 1.760

Decision Rule: To reject the null hypothesis if the t-test is greater than the critical value.

Conclusion: We reject H_o and there is sufficient evidence to conclude that the test scores for contact address s less than Noncontact athletes.

To calculate r²

The percentage of the variance is;

r^2 = \dfrac{t^2}{t^2 + df}

r^2 = \dfrac{2.2450^2}{2.2450^2 + 14}

r^2 = \dfrac{5.040025}{5.040025+ 14}

r^2 = 0.2647

7 0
3 years ago
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