Ask question

Ask question

All categories

Morgarella [4.7K]

3 years ago

5

Please help, will give brainliest to correct answer!

2 answers:

Tasya [4]3 years ago

8 0

If I can remember correctly... I've done this one before and had gotten it right. (It's been awhile.) I think it was the 3rd one. Hope it helps! Please forgive me if I remembered incorrectly. But I'm 100% sure that the 3rd one is the right one! hope it helps! :)

Papessa [141]3 years ago

3 0

The answer is 7/9.Hope it helps

You might be interested in

The quotient of 6 cubed and 4 squared

m_a_m_a [10]

ANSWER

13.5

EXPLANATION

We write 6 cubed as 6³

We write 4 squared as 4²

The quotient of 6 cubed and 4 squared is written as

$\frac{ {6}^{3} }{ {4}^{2} }$

We expand to obtain:

$\frac{6 \times 6 \times 6}{4 \times 4}$

Cancel out the common factors to get,

$\frac{3 \times 3 \times 3}{2}$

This simplifies to

$\frac{27}{2} = 13.5$

6 0

4 years ago

Prouvez par récurrence que quel que soit n EN\{0}, on a

Vanyuwa [196]

The left side is equivalent to

$\displaystyle \sum_{k=1}^n \frac1{k(k+1)}$

When n = 1, we have on the left side

$\displaystyle \sum_{k=1}^1 \frac1{k(k+1)} = \frac1{1\cdot2} = \frac12$

and on the right side,

$1 - \dfrac1{1+1} = 1 - \dfrac12 = \dfrac12$

so this case holds.

Assume the equality holds for n = N, so that

$\displaystyle \sum_{k=1}^N \frac1{k(k+1)} =1 - \frac1{N+1}$

We want to use this to establish equality for n = N + 1, so that

$\displaystyle \sum_{k=1}^{N+1} \frac1{k(k+1)} = 1 - \frac1{N+2}$

We have

$\displaystyle \sum_{k=1}^{N+1} \frac1{k(k+1)} = \sum_{k=1}^N \frac1{k(k+1)} + \frac1{(N+1)(N+2)}$

$\displaystyle \sum_{k=1}^{N+1} \frac1{k(k+1)} = 1 - \frac1{N+1} + \frac1{(N+1)(N+2)}$

$\displaystyle \sum_{k=1}^{N+1} \frac1{k(k+1)} = 1 - \frac{N+2}{(N+1)(N+2)} + \frac1{(N+1)(N+2)}$

$\displaystyle \sum_{k=1}^{N+1} \frac1{k(k+1)} = 1 - \frac{N+1}{(N+1)(N+2)}$

$\displaystyle \sum_{k=1}^{N+1} \frac1{k(k+1)} = 1 - \frac1{N+2}$

and this proves the claim.

6 0

3 years ago

When Legs jumps 2 times and takes 13 steps forward, he lands in the same place as when he jumps 4 times and takes 5 steps backwa

tangare [24]

Answer:

9 steps

Step-by-step explanation:

Let $x$ be the number of jumps

and $y$ be the number of steps

So the first case

$2x+13y$

Second case

$4x-5y$

Both cover equal distances so

$2x+13y=4x-5y$

$\Rightarrow 2x-4x=-5y-13y$

$\Rightarrow 2x=18y$

$\Rightarrow x=9y$

So, one jumps is 9 steps.

4 0

3 years ago

Find the area of the shape

vova2212 [387]

37.68 is the area of the Pac-Man

5 0

3 years ago

Read 2 more answers

Please help me i need to get it turned in

bekas [8.4K]

Answer:

UWU kalabaw

Step-by-step explanation:

UWU kalabaw

8 0

3 years ago