Its a simultaneous equation:
lets make "x" the used games and "y" the new ones
4x + 2y = 84
6x + y = 78. (multiply this by 2 to cancel out y)
12x + 2y = 156
so now we subtract them:
12x - 4x = 156 - 84
x = 9
used games cost $9
new games cost 78 - 6(9) = $24
Janet has $120 but she already bought 3 NEW games so:
120 - 3(24) = $48 left
48/9 = how many used ones she can buy = 5. something
she can buy 5 used
Answer:
Nwm miałem to dawno powodzenia
Answer:
Solve for
n
by simplifying both sides of the equation, then isolating the variable.
n
=
2
Step-by-step explanation:
Answer:
<u>3.4</u>
Step-by-step explanation:
Converting all terms to multiples of 10³ :
- 4 × 10² + 3 × 10³
- 0.4 x 10³ + 3 x 10³
- (0.4 + 3) × 10³
- <u>3.4</u> × 10³
Principal: $49,000
Depreciation Rate: 50%
Depreciation Time: 5 years
Exponential Function: y = 49,000 (0.50)^x
Plug it in: y = 49,000 (0.50)^4
0.5^4= 0.0625
0.0625 x 49,000 = 3062.5
Value of Car after 20 years: 3062.5
Now, we need to find out how much the car decreases in ONE year.
Half of 3062.5 = 1531.25
1531.25/5 = 306.25
3062.5 - 306.25 = 2756.25
Value of car after 21 years: $2756 ---> 2800 (nearest hundred dollars my bad)
Hope this helps! Have a great day!
