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vampirchik [111]
3 years ago
7

Multiply.

Mathematics
1 answer:
Crank3 years ago
8 0
The main rules that we use here are :

i) \sqrt{a \cdot b}=  \sqrt{a} \cdot \sqrt{b} for nonnegative values a and b.

ii) \sqrt{a} \cdot  \sqrt{a} =a.


Thus, first 'decompose' the numbers in the radicals into prime factors:

4 \sqrt{3} \cdot 10 \cdot  \sqrt{2\cdot2\cdot3}\cdot  \sqrt{2\cdot 3}\cdot  \sqrt{2}..

By rule (i) we write:

4 \sqrt{3} \cdot 10 \cdot \sqrt{2}\cdot \sqrt{2}\cdot \sqrt{\cdot3}\cdot \sqrt{2} \cdot  \sqrt{3} \cdot \sqrt{2}.

We can collect these terms as follows:

40 \sqrt{3}\cdot (\sqrt{3}\cdot \sqrt{3}) \cdot (\sqrt{2}\cdot \sqrt{2}) \cdot( \sqrt{2} \cdot \sqrt{2}), and by rule (ii) we have:

40 \sqrt{3}\cdot 3 \cdot 2 \cdot2=40\cdot12\cdot \sqrt{3}=480 \sqrt{3}.


Answer: 480 \sqrt{3}.
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Let f(t) give the number of liters of fuel oil burned in t days, and w(r) the liters burned in r weeks. Find a formula for w by
viktelen [127]

Answer:

7 f(t)

Step-by-step explanation:

So, our f(t) is the number of liters burned in t days. If t is 1, f(t)=f(1) and so on for every t.

w(r) id the number of liters in r weeks. This is, in one week there are w(1) liters burned.

As in one week there are 7 days, we can replace the r, that is a week, by something that represents 7 days. As 1 day is represented by t, one week can be 7t (in other words r = 7t). So, we have that the liters burned in one week are:

w(r) = w[7f(t)]

So, we represented the liters in one week by it measure of days.

So, we can post that the number of liters burned in 7 days is the same as the number of liters burned 1 day multiplied by 7 times. So:

w (r) = w[7 f(t)] = 7 f(t)

Here we hace the w function represented in terms of t instead of r.

3 0
3 years ago
Robert is writing a paper for language arts class he can write one third of the page in 1/4 of an hour at what rate is Robert wr
Mars2501 [29]
He's writing one paper every 3/4 of an hour

1/3: 15 minutes
2/3: 30 min
3/3: 45 minutes

Or, one paper every 45 minutes/ 3/4 of an hour
7 0
2 years ago
Two car washers, Michelle and Nancy, are working on your car. Michelle can complete the work in 6 hours, while Nancy can complet
g100num [7]
Time taken by Michelle to complete the work alone = 6 hours
Time taken by Nancy to complete the work alone = 3 hours
Now, when they both are working on the same job for 1 hour, 
Amount of job completed = (1/6) + (1/3) 
                                         = (1 + 2)/6 
                                         = 3/6 
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3 0
3 years ago
Read 2 more answers
F(x)=-3x-7<br> if f(x)=-61, find x
Mars2501 [29]

Answer:

18

Step-by-step explanation:

You have to set the equations equal to each other and then solve for the variable.

Hope this helps:)

4 0
2 years ago
Please solve the eqution<br> Cos4x + cos2x - 2 =0
horrorfan [7]

cos4x = cos2x

We know that:

cos2x = 1-2cos^2 x

==> cos4x = 1-2cos^2 (2x)

Now substitute:

==> 1-2cos^2 (2x) = cos2x

==> 2cos^2 (2x) + cos2x - 1 = 0

Now factor:

==> (2cos2x -1)(cos2x + 1) = 0

==> 2cos2x -1 = 0 ==> cos2x =1/2 ==> 2x= pi/3

==> x1= pi/6 , 7pi/6

==> x1= pi/6 + 2npi

==> x2= 7pi/6 + 2npi

==> cos2x = -1 ==> 2x= pi ==> x3 = pi/2 + 2npi.

<span>==> x= { pi/6+2npi, 7pi/6+2npi, pi/2+2npi}</span>

6 0
3 years ago
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