Answer:
7 f(t)
Step-by-step explanation:
So, our f(t) is the number of liters burned in t days. If t is 1, f(t)=f(1) and so on for every t.
w(r) id the number of liters in r weeks. This is, in one week there are w(1) liters burned.
As in one week there are 7 days, we can replace the r, that is a week, by something that represents 7 days. As 1 day is represented by t, one week can be 7t (in other words r = 7t). So, we have that the liters burned in one week are:
w(r) = w[7f(t)]
So, we represented the liters in one week by it measure of days.
So, we can post that the number of liters burned in 7 days is the same as the number of liters burned 1 day multiplied by 7 times. So:
w (r) = w[7 f(t)] = 7 f(t)
Here we hace the w function represented in terms of t instead of r.
He's writing one paper every 3/4 of an hour
1/3: 15 minutes
2/3: 30 min
3/3: 45 minutes
Or, one paper every 45 minutes/ 3/4 of an hour
Time taken by Michelle to complete the work alone = 6 hours
Time taken by Nancy to complete the work alone = 3 hours
Now, when they both are working on the same job for 1 hour,
Amount of job completed = (1/6) + (1/3)
= (1 + 2)/6
= 3/6
= 1/2
So in 1 hours time they both will complete half of the job. Then in 2 hours Michelle and Nancy will complete the total job. I hope the answer has come to your help.
Answer:
18
Step-by-step explanation:
You have to set the equations equal to each other and then solve for the variable.
Hope this helps:)
cos4x = cos2x
We know that:
cos2x = 1-2cos^2 x
==> cos4x = 1-2cos^2 (2x)
Now substitute:
==> 1-2cos^2 (2x) = cos2x
==> 2cos^2 (2x) + cos2x - 1 = 0
Now factor:
==> (2cos2x -1)(cos2x + 1) = 0
==> 2cos2x -1 = 0 ==> cos2x =1/2 ==> 2x= pi/3
==> x1= pi/6 , 7pi/6
==> x1= pi/6 + 2npi
==> x2= 7pi/6 + 2npi
==> cos2x = -1 ==> 2x= pi ==> x3 = pi/2 + 2npi.
<span>==> x= { pi/6+2npi, 7pi/6+2npi, pi/2+2npi}</span>