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ICE Princess25 [194]
3 years ago
12

Which of the following represents a function?

Mathematics
1 answer:
-Dominant- [34]3 years ago
3 0
It would be D it’s really ez
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Cot^2x/cscx-1=1+sinx/sinx
KATRIN_1 [288]
\bf \textit{difference of squares}
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(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)
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sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta)\\\\
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\cfrac{cot^2(x)}{csc(x)-1}=\cfrac{1+sin(x)}{sin(x)}\impliedby \textit{let's do the left-hand-side}

\bf \cfrac{\quad \frac{cos^2(x)}{sin^2(x)}\quad }{\frac{1}{sin(x)}-1}\implies \cfrac{\quad \frac{cos^2(x)}{sin^2(x)}\quad }{\frac{1-sin(x)}{sin(x)}}\implies \cfrac{cos^2(x)}{sin^2(x)}\cdot \cfrac{sin(x)}{1-sin(x)}
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\cfrac{cos^2(x)}{sin(x)}\cdot \cfrac{1}{1-sin(x)}\implies \cfrac{cos^2(x)}{sin(x)[1-sin(x)]}

\bf \cfrac{1-sin^2(x)}{sin(x)[1-sin(x)]}\implies \cfrac{1^2-sin^2(x)}{sin(x)[1-sin(x)]}
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\cfrac{\underline{[1-sin(x)]}~[1+sin(x)]}{sin(x)\underline{[1-sin(x)]}}\implies \cfrac{1+sin(x)}{sin(x)}
5 0
3 years ago
Write the point-slope form of the equation for a line that passes through (–1, 4) with a slope of 2
lozanna [386]
Point slope form: y-y_{1}=m(x-x_{1})
Answer: y-4=2(x+1)
4 0
3 years ago
Read 2 more answers
Enter an equation and an answer to the following question:
sergey [27]
35=x*10/100
x=10*35=350$

the original list price is $350
6 0
3 years ago
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1. A field in the form of a parallelogram has one
klio [65]

Answer:

420m²

Step-by-step explanation:

Given that:

Length of diagonal = 42m

Lenght of outlying vertice = 10 m

Area of paralellogram = 2 " (area of triangle)

Area of triangle = 1/2 * base * height

Hence,

Area of parallelogram :

Area = 2(0.5 * 42 * 10)

Area = 2 (210)

Area = 420m²

8 0
3 years ago
if a stone is dropped from a cliff that is 122.5m high then its height in meters after t seconds is h=122.5-4.9t^2. find its vel
Natalija [7]

Answer:

Step-by-step explanation:

Let t = 2

h = 122.5 - 4.9·2² = 122.5-19.6 = 102.9

4 0
3 years ago
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