Given triangle ABC with coordinates A(−6, 4), B(−6, 1), and C(−8, 0), and its image A′B′C′ with A′(−2, 0), B′(−5, 0), and C′(−6,
Zinaida [17]
Answer:
The line of reflection is at y = x+6.
Step-by-step explanation:
The perpendicular bisector of AA' is a line with slope 1 through the midpoint of AA', which is (-4, 2). In point-slope form, the equation is ...
y = 1(x +4) +2
y = x + 6 . . . . . . . line of reflection
Answer:
6w-60x+6
Step-by-step explanation:
6(w-10x+1)
6w+6(-10)+6*1
6w-60x+6
Answer:
I don't know how to do this. I'm so sorry that I couldn't help!!
Step-by-step explanation:
Answer:
X= 6.2 + 68 ???
Step-by-step explanation:
I'm not sure that's what I would write in an exam