We have the following equations:

So we are asked to write a system of equations or inequalities for each region and each point.
Part a)Region Example A
Region B.
Let's take a point that is in this region, that is:

So let's find out the signs of each inequality by substituting this point in them:

So the inequalities are:
Region C.
A point in this region is:

So let's find out the signs of each inequality by substituting this point in them:

So the inequalities are:
Region D.
A point in this region is:

So let's find out the signs of each inequality by substituting this point in them:

So the inequalities are:
Point P:This point is the intersection of the two lines. So let's solve the system of equations:

Accordingly, the point is:
Point q:
This point is the

of the line:

So let:

Then

Therefore, the point is:

Part b)
The coordinate of a point within a region must satisfy the corresponding system of inequalities. For each region we have taken a point to build up our inequalities. Now we will take other points and prove that these are the correct regions.
Region Example A
The origin is part of this region, therefore let's take the point:

Substituting in the inequalities:

It is
true.
Region B.
Let's take a point that is in this region, that is:

Substituting in the inequalities:

It is
true
Region C.
Let's take a point that is in this region, that is:

Substituting in the inequalities:

It is
true
Region D.
Let's take a point that is in this region, that is:

Substituting in the inequalities:

It is
true