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gogolik [260]
3 years ago
7

A skydiver accelerates from REST at 9.8 m/s² for the first 5m of their fall. Calculate their final speed. (Give your answer to 2

significant figures)
Physics
1 answer:
Kaylis [27]3 years ago
5 0

Answer:

The final speed is 9.89 m/s.

Explanation:

Initial speed of skydiver is 0 as it was rest.

Acceleration of the skydiver is 9.8 m/s²

It accelerates for the first 5 m of their fall.

It is required to find their final speed. Let v is the final speed. It can be calculated using third equation of motion.

v^2-u^2=2as

Here, u = 0

a = 9.8 m/s²

s = 5 m

v=\sqrt{2gs} \\\\v=\sqrt{2\times 9.8\times 5} \\\\v=9.89\ m/s

So, the final speed is 9.89 m/s.

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3 0
3 years ago
at certain times the demand for electric energy is low and electric energy is used to pump water to a reservoir 45 m above the g
Readme [11.4K]

The mass of water that must be raised is 5.25\cdot 10^7 kg

Explanation:

Since the process is 70% efficiency, the power in output to the turbine can be written as

P_{out} = 0.70 P_{in}

where P_{in} is the power in input.

The power in input can be written as

P_{in} = \frac{W}{t}

where

W is the work done in lifting the water

t = 3 h = 10,800 s is the time elapsed

The work done in lifting the water is given by

W=mgh

where

m is the mass of water

g=9.8 m/s^2 is the acceleration of gravity

h = 45 m is the height at which the water is lifted

Combining the three equations together, we get:

P_{out} = 0.70 \frac{mgh}{t}

Where

P_{out} = 150 MW = 150\cdot 10^6 W

And solving for m, we find:

m=\frac{Pt}{0.70gh}=\frac{(1.50\cdot 10^6)(10800)}{(0.70)(9.8)(45)}=5.25\cdot 10^7 kg

Learn more about power:

brainly.com/question/7956557

#LearnwithBrainly

3 0
4 years ago
A circular solenoid of radius R = 2cm passes through a square loop of wire with 1 turn and sides of length ℓ = 5cm. The solenoid
ankoles [38]
The answer for this problem is D
4 0
4 years ago
A horizontal force of 750 N is needed to overcome the force of static friction between a level floor and a 250-kg crate. What is
loris [4]

Answer:

The acceleration of the crate is 1.82\ m/s^2.

Explanation:

Given that,

Force, F = 750 N

Mass of the crate, m = 250 kg

The coefficient of friction is 0.12.

We need to find the acceleration of the crate. The net force acting on the crate is given by :

F=ma\\\\F-f=ma

f is frictional force, f=\mu N=\mu mg

F-\mu mg=ma\\\\a=\dfrac{F-\mu mg}{m}\\\\a=\dfrac{750-0.12\times 250\times 9.8}{250}\\\\a=1.82\ m/s^2

So, the acceleration of the crate is 1.82\ m/s^2. Hence, this is the required solution.

4 0
3 years ago
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