Question

A skydiver accelerates from REST at 9.8 m/s² for the first 5m of their fall. Calculate their final speed. (Give your answer to 2 significant figures)

Answer 1

Answer:

The final speed is 9.89 m/s.

Explanation:

Initial speed of skydiver is 0 as it was rest.

Acceleration of the skydiver is 9.8 m/s²

It accelerates for the first 5 m of their fall.

It is required to find their final speed. Let v is the final speed. It can be calculated using third equation of motion.

$v^2-u^2=2as$

Here, u = 0

a = 9.8 m/s²

s = 5 m

$v=\sqrt{2gs} \\\\v=\sqrt{2\times 9.8\times 5} \\\\v=9.89\ m/s$

So, the final speed is 9.89 m/s.