Answer:
18 years old you would be
Answer:
4Joules
Step-by-step explanation:
According to Hooke's law which states that extension of an elastic material is directly proportional to the applied force provide that the elastic limit is not exceeded. Mathematically,
F = ke where
F is the applied force
K is the elastic constant
e is the extension
If a spring exerts a force of 6 N when stretched 3 m beyond its natural length, its elastic constant 'k'
can be gotten using k = f/e where
F = 6N, e = 3m
K = 6N/3m
K = 2N/m
Work done on an elastic string is calculated using 1/2ke².
If the spring is stretched 2 m beyond its natural length, the work done on the spring will be;
1/2× 2× (2)²
= 4Joules
Answer:
the son is 2
man is 26
+10 yrs
son=12
man=36
Step-by-step explanation:
Let the son's age be x.
Then the father's age is 13x.
In ten years their ages will be (x+10) and (13x+10).
(13x+10)=3(x+10)
13x+10=3x+30
10x=20
x=2
The son is 2 years old.
Answer:
B. 7.9 in^2
Step-by-step explanation:
Part I.
Finding the fraction of the circle that is the sector
To start, let’s find the fraction of the circle that the sector covers. Since the measure of the central angle is 36, we get 36/360 or 1/10 of the circle.
Part II.
Finding the area of the Circle
The area of a circle is pi*r^2. Since r=5, then the area is 25pi.
Part III.
Finding the area of the sector.
Since the sector is 1/10 of the circle, its area is 1/10 of the circle’s area. So the area of the sector is 25/10*pi or (5/2)pi. This is approximately 7.9 in^2.
