Answer:
FV= $1,725.22
Step-by-step explanation:
Giving the following information:
Present value (PV)= $2,000
Decrease rate (d)= 3% per week
Number of weeks (n)= 5
<u>To calculate the future value of the fish after 5 weeks, we need to use the following formula:</u>
FV= PV / (1 + d)^n
FV= 2,000 / (1.03^5)
FV= $1,725.22
Answer:
The probability that it takes more than 30 lines of code until Joe finds his first bug is 0.2821.
Step-by-step explanation:
Let <em>X</em> = number of bugs in every 25 lines of code.
The probability of the random variable <em>X</em> is,
.
The random variable <em>X</em> follows a Geometric distribution.
A Geometric distribution is the probability distribution of the number of Bernoulli trials needed before the first success.
The probability mass function of Geometric distribution is:
![P(X=x)=(1-p)^{x-1}p; x=0,1,2,3...](https://tex.z-dn.net/?f=P%28X%3Dx%29%3D%281-p%29%5E%7Bx-1%7Dp%3B%20x%3D0%2C1%2C2%2C3...)
Compute the probability that it takes more than 30 lines of code until Joe finds his first bug as follows:
P (X > 30) = 1 - P (X ≤ 30)
![=1-\sum\limits^{30}_{x=0}[(1-\frac{1}{25})^{x-1}\frac{1}{25}]\\=1-0.7179\\=0.2821](https://tex.z-dn.net/?f=%3D1-%5Csum%5Climits%5E%7B30%7D_%7Bx%3D0%7D%5B%281-%5Cfrac%7B1%7D%7B25%7D%29%5E%7Bx-1%7D%5Cfrac%7B1%7D%7B25%7D%5D%5C%5C%3D1-0.7179%5C%5C%3D0.2821)
Thus, the probability that it takes more than 30 lines of code until Joe finds his first bug is 0.2821.
The answer to your problem is -8/-3
Answer:
Yeah about that we need the dot plot for us to solve it lol
Step-by-step explanation:
Answer:
y=-2x-2
Step-by-step explanation:
y+4=-2(x-1)
y+4=-2x+2
y=-2x+2-4
y=-2x-2