Question

What is the equation of a line that passes through points (2,0) and (6,-4)

Answer 1

Answer:

y = - x + 2

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (2, 0) and (x₂, y₂ ) = (6, - 4)

m = $\frac{-4-0}{6-2}$ = $\frac{-4}{4}$ = - 1, thus

y = - x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (6, - 4), then

- 4 = - 6 + c ⇒ c = - 4 + 6 = 2

y = - x + 2 ← equation of line