Answer:
mean = sum of the terms/total no. of terms
mean = (16+12+13+22)/4
mean = 63/4 or 15.75
.4706 or 47.06%
you would add the boys and the girls and then divide divide the boys by the total student in the bag
Answer:
x = 183
Step-by-step explanation:
(x -73)° + x° +67° = 360°
x-73+ x +67 = 360
x + x -73 +67 = 360
2x-6 = 360
2x = 360+6
x = 366÷2
x = 183
Check:
(183 - 73) = 110° , x = 183° , 67°
110° + 183° + 67° = 360°
A wright a system of equation to describe the situation
Answer:
Therefore r'(t) =-k sin t i + k cos t j and |r'(t)| = k so T(t) = r'(t)/|r'(t)| = -sin t i + cos t j and T'(t) = -cos t i- sin t j . This gives |T'(t)| = 1, so using this equation, we have κ(t) = |T'(t)|/|r'(t)| = 1/k.
Step-by-step explanation:
We are already given the definition of curvature and the parametrization needed to find the curvature of the circle. In genecral the curvature κ is equal to κ(t)=|T'(t)|/|r'(t)| where r(t) is a parametrization of the curve and T(t) is the normalized tangent vector respect to the parametrization, that is, T(t)=r'(t)/|r'(t)|.
Now, using the derivatives of sines and cosines, and the definition of norm, we obtain that:
r(t) = k cos t i + k sin t j ⇒ r'(t)=-k sin t i + k cos t j ⇒|r'(t)|²=sin²t+cos²t=1
T(t) = r'(t)/|r'(t)|=-sin t i +cos t j ⇒ T'(t)= -cos t i - sin t j ⇒|T'(t)|²=cos²t+sin²t=1
