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3 years ago

What is solve for f 5h(-m+f)=6

Mathematics

1 answer:

Sergio [31]3 years ago

4 0

Answer:

F = 6 over 5h + m

Hope I helped you out :)

Step-by-step explanation:

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Samantha needs to bake at least 120 pot pies to sell at her restaurant. she can bake 12 pot pies per hour and 15 veggie pot pies

Veronika [31]

Answer:

y>(line under >) - 4/5x + 8

Step-by-step explanation:

Phrase "at least" indicates that the total number of pies is greater than or equal to 120.

The number of chicken pot pies Samantha makes is 12x, and the number of veggie pot pies she makes is 15y.

Use this information to create the inequality:

12x + 15y >(line under >) 120

Simplify by solving for y to get this inequality:

y >(line under >) - 4/5x + 8

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2 years ago

Ryan can text 22 words in 4 minutes. At this rate, how many words could he text in 12 minutes? Fill out the table of equivalent

aleksandrvk [35]

The answer would be 66
Explanation: first you have to divide the minutes so 12 divided by 4 equals 3 so you would take the three and multiply that by 22. So 22x3 is equal to 66

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3 years ago

What is the answer to -7(-3n 2)?

sergey [27]

21n+14 you have to find the value of n

8 0

3 years ago

The sum of two numbers is 35 the smaller number is 7 less than the larger number what are the numbers

Keith_Richards [23]

14 and 21

14 + 7 is 21 and 21 + 14 is 35.

5 0

3 years ago

Match the cofactors to their corresponding entries in the matrix.

Masja [62]

Answer:

The co-factors and their values are shown in the table below.

Step-by-step explanation:

We are given the matrix, $\begin{bmatrix}3&7&1\\7&1&-3\\8&5&1\end{bmatrix}$ .

It is required to match the co-factors with the corresponding values.

As, the co-factors are given by,

$A_{c_{ij}}$ = $(-1)^{i+j}(d)$ , where the d= determinant of the matrix after removing the i- row and j- column.

So, we have,

1. $A_{c_{11}}$ .

So, $A_{c_{11}}=(-1)^{1+1}(1\times 1-5\times (-3))$

i.e. $A_{c_{11}}=(-1)^{2}(1+15)=16$

2. $A_{c_{13}}$ .

So, $A_{c_{13}}=(-1)^{1+3}(7\times 5-1\times 8)$

i.e. $A_{c_{13}}=(-1)^{4}(35-8)=27$

3. $A_{c_{21}}$ .

So, $A_{c_{21}}=(-1)^{2+1}(7\times 1-5\times 1)$

i.e. $A_{c_{21}}=(-1)^{3}(7-5)=-2$

4. $A_{c_{22}}$ .

So, $A_{c_{22}}=(-1)^{2+2}(3\times 1-8\times 1)$

i.e. $A_{c_{22}}=(-1)^{4}(3-8)=-5$

5. $A_{c_{31}}$ .

So, $A_{c_{31}}=(-1)^{3+1}(7\times (-3)-1\times 1)$

i.e. $A_{c_{31}}=(-1)^{4}(-21-1)=-22$

Thus, we get,

Co-factor Value

$A_{c_{11}}$ 16

$A_{c_{13}}$ 27

$A_{c_{21}}$ -2

$A_{c_{22}}$ -5

$A_{c_{31}}$ -22

4 0

2 years ago