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Deffense [45]
4 years ago
11

A circle is centered on point B, Points A, C and D lie on its circumference. if ABC measures 122 degrees, what does ADC measures

?
Mathematics
1 answer:
iren2701 [21]4 years ago
5 0

Answer:

61°

Step-by-step explanation:

Angle extended to the circumference is half the angle at the centre

ADC = ½ ABC = ½ × 122 = 61

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A square number and a multiple of 3 have a total of 90 what r the 2 numbers
Alecsey [184]

Hello,

Let's x² the square number

and 3*y the multiple of 3.

x^2+3y=90\\\\\boxed{y=-\dfrac{1}{3} x^2+30}\\\\

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Point A is the midpoint of side XZ and point B is the
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Read 2 more answers
What are the zeros of the quadratic function f(x) = 6x2 – 24x + 1?<br><br> fast please
xxTIMURxx [149]

Answer:      6(x²-4x+4-4)+1=0, 6(x-2)²-24+1=0, 6(x-2)²=23, x-2=±√(23/6), x=2±√(23/6)=2±1.95789, so x=3.95789 or 0.04211 approx. these are the zeros.

step by step explanation:

\boxed{\boxed{\dfrac{12+\sqrt{138}}{6},\ \dfrac{12-\sqrt{138}}{6}}}

Solution-

The quadratic function is,

6x^2-24x + 1

a = 6, b = -24, c = 1

x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

=\dfrac{-(-24)\pm \sqrt{-24^2-4\cdot 6\cdot 1}}{2\cdot 6}

=\dfrac{24\pm \sqrt{576-24}}{12}

=\dfrac{24\pm \sqrt{552}}{12}

=\dfrac{24\pm 2\sqrt{138}}{12}

=\dfrac{12\pm \sqrt{138}}{6}

=\dfrac{12+\sqrt{138}}{6},\ \dfrac{12-\sqrt{138}}{6}

4 0
4 years ago
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