PLEASE DO NOT ANSWER THIS EMPTY OR ADD A LINK OR SAY "Answer is in here!" I WILL REPORT YOU IF YOU DO. I DO NOT TAKE FILES PLEAS
E PLEASE PLASE.
2 answers:
Answer:
I think the answer(s) are m = -3 and/or m = 1.5 because they both hit the lines.
(sorry if I'm wrong or this wasn't helpful)
Step-by-step explanation:
Three ways to find the slope of a line:
1. You may have two points ( x 1 , y 1 ) and ( x 2 , y 2 ) (often one or both of these points may be intercepts of the x and/or y axes). The slope is given by the equation
y
2
−
y
1
m = -------------- (<- that's supposed to be a fraction btw)
x 2 − x 1
2. You may have a linear equation that is either in the form or can be manipulated into the form
y = m x + b .
In this case the slope is m (the coefficient of x ).
3. If the line is a tangent to another function, you may have (or be able to determine) the slope of the tangent as the derivative of the function. Normally in this case the derivative is a function expressed in terms of x and you need to substitute the value of x into this function for the required location.
<3 Enjoy,
Dea
You might be interested in
Step-by-step explanation:
I think your question is missed of key information, allow me to add in and hope it will fit the original one.
Please have a look at the attached photo.
My answer:
Question 1: Please see the answer at the photo, remember that when number of quartz is = 1 , Price per quartz = 2. This will be merge against each other.
This step will be repeated for the remaining figure.
Question 2:
As an be seen from the scatter plot, price per quart decrease when the number of quarts increase so the relation between the two variable show a negative association
Hope it will find you well.
1. Domain.
We have
in the denominator, so:
![x^2-2x-3\neq0\\\\(x^2-2x+1)-4\neq0\\\\(x-1)^2-4\neq0\\\\(x-1)^2-2^2\neq0\qquad\qquad[\text{use }a^2-b^2=(a-b)(a+b)]\\\\(x-1-2)(x-1+2)\neq0\\\\ (x-3)(x+1)\neq0\\\\\boxed{x\neq3\qquad\wedge\qquad x\neq-1}](https://tex.z-dn.net/?f=x%5E2-2x-3%5Cneq0%5C%5C%5C%5C%28x%5E2-2x%2B1%29-4%5Cneq0%5C%5C%5C%5C%28x-1%29%5E2-4%5Cneq0%5C%5C%5C%5C%28x-1%29%5E2-2%5E2%5Cneq0%5Cqquad%5Cqquad%5B%5Ctext%7Buse%20%7Da%5E2-b%5E2%3D%28a-b%29%28a%2Bb%29%5D%5C%5C%5C%5C%28x-1-2%29%28x-1%2B2%29%5Cneq0%5C%5C%5C%5C%0A%28x-3%29%28x%2B1%29%5Cneq0%5C%5C%5C%5C%5Cboxed%7Bx%5Cneq3%5Cqquad%5Cwedge%5Cqquad%20x%5Cneq-1%7D)
So there is a hole or an asymptote at x = 3 and x = -1 and we know, that answer B) is wrong.
2. Asymptotes:
We have only one asymptote at x = -1 (and hole at x = 3), thus the correct answer is A)
We have
So there is a hole or an asymptote at x = 3 and x = -1 and we know, that answer B) is wrong.
2. Asymptotes:
We have only one asymptote at x = -1 (and hole at x = 3), thus the correct answer is A)